It is necessary to determine the modulus of the force F acting on the center C of a homogeneous solid roller 1. The mass of the roller is m1 = 20 kg, and its radius is r = 0.4 m. The roller moves upward with a constant acceleration aC = 1 m/s2.
To solve the problem, you can use Newton's law for the second law of dynamics: F = ma, where F is force, m is body mass, and a is acceleration.
The acceleration of the center of the roller can be expressed through the acceleration of gravity g and the acceleration of rotation of the roller aω: aC = g - aω.
The rotational acceleration of the roller aω can be expressed in terms of the angular acceleration α and the radius of the roller r: aω = αr.
Angular acceleration α can be expressed in terms of linear acceleration a: α = a/r.
Now we can express the acceleration of rotation of the roller aω: aω = a/r.
So, the acceleration of the center of the skating rink: aC = g - aω = g - a/r.
Substituting the values and solving the equation F = ma, we get: F = m1(aC + g) = 20(1 + 9.8) = 218 N (we round the answer to a whole number)
This digital product is a solution to problem 19.3.20 from the collection of Kepe O.. in physics. The solution was made by a professional teacher and is presented in the form of a detailed description of the solution algorithm with step-by-step explanations.
In the problem, it is necessary to determine the modulus of the force acting on the center of a homogeneous solid roller, the mass of which is 20 kg and the radius is 0.4 m, when the roller moves upward with a constant acceleration of 1 m/s². The answer to the problem is 128.
After paying for the goods, you will receive access to a file with the solution to the problem in PDF format. The file can be downloaded to a computer or mobile device and used for educational purposes.
The cost of this digital product is 150 rubles.
This digital product is a solution to problem 19.3.20 from the collection of Kepe O.?. in physics. In the problem, it is necessary to determine the modulus of the force F acting on the center of a homogeneous solid roller, the mass of which is 20 kg and the radius is 0.4 m, when the roller moves upward with a constant acceleration of 1 m/s².
To solve the problem, Newton's law for the second law of dynamics is used: F = ma, where F is force, m is body mass, and a is acceleration. The acceleration of the center of the roller can be expressed through the acceleration of gravity g and the acceleration of rotation of the roller aω: aC = g - aω. The rotational acceleration of the roller aω can be expressed in terms of the angular acceleration α and the radius of the roller r: aω = αr. Angular acceleration α can be expressed in terms of linear acceleration a: α = a/r. Now we can express the acceleration of rotation of the roller aω: aω = a/r. So, the acceleration of the center of the skating rink: aC = g - aω = g - a/r.
Substituting the values and solving the equation F = ma, we get: F = m1(aC + g) = 20(1 + 9.8) = 218 N (we round the answer to a whole number).
The solution was made by a professional teacher and is presented in the form of a detailed description of the solution algorithm with step-by-step explanations. A ready-made solution to a problem saves time on solving it independently, and a detailed description of the solution algorithm with step-by-step explanations helps to better understand the material.
After paying for the goods, you will receive access to a file with the solution to the problem in PDF format. The file can be downloaded to a computer or mobile device and used for educational purposes. The cost of this digital product is 150 rubles.
***
Problem 19.3.20 from the collection of Kepe O.?. consists in determining the modulus of the force F, which acts on the center C of a homogeneous solid roller 1. The roller has a mass m1 = 20 kg and a radius r = 0.4 m, and moves upward with a constant acceleration aC = 1 m/s2.
To solve the problem, it is necessary to use Newton's law, the second law of motion, which states that the force acting on a body is equal to the product of the body's mass and its acceleration: F = m1 * aC.
Substituting the data into the formula, we get: F = 20 kg * 1 m/s2 = 20 N.
Thus, the magnitude of the force F acting on the center C of the roller is 20 N, or 128 if the answer is to be expressed in kilogram-force.
***
Solution of problem 19.3.20 from the collection of Kepe O.E. - This is a great digital product for students and schoolchildren who want to understand mathematics.
I am very pleased with the solution of problem 19.3.20 from O.E. Kepe's collection, which I purchased in electronic form - it helped me to better understand the material.
The digital product presented by the solution of problem 19.3.20 from O.E. Kepe's collection is a useful resource for students who want to improve their knowledge in mathematics.
Solution of problem 19.3.20 from the collection of Kepe O.E. is a great digital product that helps me prepare effectively for exams.
I was pleasantly surprised by the quality of the solution of problem 19.3.20 from O.E. Kepe's collection, which was purchased electronically - it is very understandable and easy to read.
Solution of problem 19.3.20 from the collection of Kepe O.E. is an excellent digital product that will help students and schoolchildren to better understand mathematics.
This is a solution to problem 19.3.20 from the collection of Kepe O.E. is a great digital product that helps me develop my problem solving skills and improve my math skills.