Solution to problem 7.7.5 from the collection of Kepe O.E.

7.7.5

Speed graph given v = v(t) movement of a point along a circle of radius R. Need to find time t, at which the normal acceleration ap = 0. Answer: 2.5.

It is necessary to find the time at which the normal acceleration of a point on a circle of radius R equals zero if the velocity graph is known v = v(t). To do this, you can use the formula for the normal acceleration of a point on a circle: ап = v^2/R. Since an is equal to zero, then v must also be equal to zero or constantly equal to some constant. So the time t, at which the normal acceleration an = 0, will correspond to the moment in time when the speed v equal to zero. In this case, this time is 2.5.

Solution to problem 7.7.5 from the collection of Kepe O.?.

We present to your attention a digital product - a solution to problem 7.7.5 from the collection of Kepe O.?. This product is intended for students and teachers who are studying physics and mathematics and need help solving problems.

In this product you will find a detailed solution to problem 7.7.5, which concerns the movement of a point along a circle of radius R and finding the time at which the normal acceleration an = 0. The solution is carried out in accordance with the methodological recommendations and describes in detail all the steps necessary to obtain the correct answer .

This digital product is available for download immediately after payment and has a beautiful html design, making it easy to use and pleasing to the eye.

Don't miss the opportunity to purchase the solution to problem 7.7.5 from the collection of Kepe O.?. and improve your knowledge in physics and mathematics!

Digital product "Solution to problem 7.7.5 from the collection of Kepe O.?." is a detailed solution to the problem of moving a point along a circle of radius R and finding the time at which the normal acceleration an = 0, corresponding to the velocity graph v = v(t). The solution is made in accordance with the methodological recommendations and describes all the necessary steps to obtain the correct answer, which is 2.5. Since the normal acceleration an is zero, the speed v must be zero or constantly equal to some constant. The solution to the problem is based on the use of the formula for the normal acceleration of a point on a circle: an = v^2/R. The digital product is available for download immediately after payment and has a beautiful html design, which makes it easy to use and pleasing to the eye. This product can be useful both for students studying physics and mathematics, and for teachers who need help solving problems.

We present to your attention a digital product - a solution to problem 7.7.5 from the collection of Kepe O.?.

This product is intended for students and teachers who are studying physics and mathematics and need help solving problems.

In this product you will find a detailed solution to Problem 7.7.5, which concerns the movement of a point along a circle of radius R and finding the time at which the normal acceleration an = 0.

To solve the problem, use the formula for the normal acceleration of a point on a circle: an = v^2/R. Since an is equal to zero, then v must also be equal to zero or constantly equal to some constant. Thus, the time t, at which the normal acceleration an = 0, will correspond to the moment of time when the speed v is equal to zero.

The graph of the speed v = v(t) of the movement of a point along a circle of radius R is already known. Therefore, to find time t, you need to find the moment when the speed v is zero. In this case, this time is 2.5.

The solution is made in accordance with the methodological recommendations and describes in detail all the steps necessary to obtain the correct answer.

This digital product is available for download immediately after payment and has a beautiful html design, making it easy to use and pleasing to the eye.

Don't miss the opportunity to purchase the solution to problem 7.7.5 from the collection of Kepe O.?. and improve your knowledge in physics and mathematics!

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Problem 7.7.5 from the collection of Kepe O.?. lies in the fact that a graph of the speed v = v(t) of the movement of a point along a circle of radius R is given, and it is necessary to find the time t at which the normal acceleration an = 0. The correct answer to the problem is: 2.5. To solve it, it is necessary to use the formula for normal acceleration an = v^2/R, where v is the speed of the point, R is the radius of the circle. Since an = 0, then v = 0 or v = sqrt(R * an). From the speed graph it can be determined that the speed of a point reaches zero twice during the period of movement, that is, the time when an = 0 is equal to half the period of movement, i.e. 2.5.

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