Solution C4-86 (Figure C4.8 condition 6 S.M. Targ 1989)

In problem C4-86 (Figure C4.8 condition 6 S.M. Targ 1989) there are two homogeneous rectangular thin plates that are rigidly connected (welded) at right angles to each other. The plates are secured by a spherical hinge (or thrust bearing) at point A, a cylindrical hinge (bearing) at point B and a weightless rod 1 (Fig. C4.0 - C4.7) or two bearings at points A and B and two weightless rods 1 and 2 (Fig. C4.8, C4.9). All rods are attached to the slabs and fixed supports with hinges. The dimensions of the slabs are indicated in the pictures; weight of the larger slab P1 = 5 kN, weight of the smaller slab P2 = 3 kN. Each of the plates is located parallel to one of the coordinate planes (the xy plane is horizontal). The plates are acted upon by a pair of forces with a moment M = 4 kN m, lying in the plane of one of the plates, and two forces. The values ​​of these forces, their directions and points of application are indicated in table. C4; in this case, the forces F1 and F4 lie in planes parallel to the xy plane, the force F2 - in the plane parallel to xz, and the force F3 - in the plane parallel to yz. The points of application of forces (D, E, N, K) are located in the corners or in the middle of the sides of the slabs. It is necessary to determine the reaction of the bonds at points A and B and the reaction of the rod (rods). When calculating, it is assumed that a = 0.6 m.

Welcome to our digital goods store! From us you can purchase the solution to problem C4-86, presented in Figure C4.8 in condition 6 from the textbook by S.M. Targa 1989. This digital product includes a detailed description of the problem, as well as a solution presented in a beautiful

Solution C4-86 (Figure C4.8 condition 6 S.M. Targ 1989) is a digital product that includes a description of the problem and its solution. In the problem there are two homogeneous rectangular thin plates, rigidly connected at right angles to each other and fixed at point A with a spherical hinge (or thrust bearing), at point B with a cylindrical hinge (bearing) and weightless rod 1. The dimensions of the plates are indicated in the figures, and the weight the larger slab P1 = 5 kN, and the smaller slab P2 = 3 kN. Each of the plates is located parallel to one of the coordinate planes (the xy plane is horizontal). The plates are acted upon by a pair of forces with a moment M = 4 kN m, lying in the plane of one of the plates, and two forces. The values ​​of these forces, their directions and points of application are indicated in table. C4. The points of application of forces (D, E, N, K) are located in the corners or in the middle of the sides of the slabs. It is necessary to determine the reaction of the bonds at points A and B and the reaction of the rod (rods). When calculating, it is assumed that a = 0.6 m.

Solving the problem includes a detailed analysis and calculation of the reactions of connections and rods using appropriate formulas and methods of mechanics. The calculation results are presented in the form of a beautifully designed report that makes it easy to understand and evaluate the results obtained.

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Solution C4-86 describes the design of two homogeneous rectangular thin plates connected at right angles and fixed at point A with a spherical hinge or thrust bearing, and at point B with a cylindrical hinge or bearing. The design also includes a weightless rod 1 or two weightless rods 1 and 2, attached to the plates and to the fixed supports by hinges or bearings.

The dimensions of the slabs are shown in the figures, and the weight of the larger slab P1 is 5 kN, and the weight of the smaller slab P2 is 3 kN. The plates are acted upon by a pair of forces with a moment M = 4 kN m, lying in the plane of one of the plates, and two forces, the values ​​of which, directions and points of application are indicated in Table. C4. The points of application of forces are in the corners or in the middle of the sides of the slabs.

It is necessary to determine the reaction of the bonds at points A and B and the reaction of the rod (rods). When calculating, it is necessary to take a = 0.6 m.

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