Solution to problem 5.1.15 from the collection of Kepe O.E.

Determining the moment of a distributed load To solve the problem, you need to know the following parameters:

  • q0 = 200 N/m - the value of the distributed load;
  • a = 3 m - distance from the beginning of the Ox axis to the beginning of the distributed load;
  • b = 6 m - the distance from the beginning of the Ox axis to the end of the distributed load.

The moment of the distributed load relative to the Ox axis is calculated by the formula: M = -q0 * (b-a)^2 / 2 Substituting the values, we get: M = -200 * (6-3)^2 / 2 = -300 Thus, the moment of the distributed load relative to the Ox axis is equal to -300 N*m.

Solution to problem 5.1.15 from the collection of Kepe O.?.

This digital product is a solution to problem 5.1.15 from the collection of Kepe O.?. in theoretical mechanics. The solution is presented in the form of text instructions and formulas that will help you solve this problem correctly.

  • Issue number: 5.1.15
  • Author of the collection: Kepe O.?.
  • Type of problem: calculation of the moment of a distributed load relative to the Ox axis

Thus, the moment of the distributed load relative to the Ox axis is equal to -300 N*m.

By purchasing this digital product, you receive a complete and correct solution to problem 5.1.15 from the collection of Kepe O.?. in theoretical mechanics. We are confident that this solution will help you complete the assignment successfully and get a good grade.

This digital product is a solution to problem 5.1.15 from the collection of Kepe O.?. in theoretical mechanics. The problem requires determining the moment of a distributed load relative to the Ox axis if the following parameters are known: the value of the distributed load q0 = 200 N/m, the distance from the beginning of the Ox axis to the beginning of the distributed load a = 3 m, and the distance from the beginning of the Ox axis to the end of the distributed load b = 6 m.

To solve the problem, you need to use the formula: M = -q0 * (b-a)^2 / 2. Substituting the known values, we get: M = -200 * (6-3)^2 / 2 = -300 N*m.

By purchasing this digital product, you receive a complete and correct solution to the problem, including text instructions and formulas that will help you complete the task. We are confident that the solution will help you complete the task successfully and get a good grade.


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Solution to problem 5.1.15 from the collection of Kepe O.?. consists in determining the moment of the distributed load relative to the Ox axis. To do this you need to use the formula:

M = ∫y*q(x)dx

where M is the moment of the distributed load relative to the Ox axis, y is the distance from the load element to the Ox axis, q(x) is the density of the distributed load, x is the coordinate of the load element.

From the conditions of the problem it is known that q0 = 200 N/m, a = 3 m and b = 6 m. Let us find the moment of the distributed load relative to the Ox axis:

M = ∫yq(x)dx = ∫0^6y200dx - ∫3^6y200dx = 600 - 900 = -300 Nm

Thus, the answer to problem 5.1.15 from the collection of Kepe O.?. - the moment of the distributed load relative to the Ox axis is equal to -300 N*m.


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