Solution of problem 2.4.6 from the collection of Kepe O.E.

2.4.6 A distributed load with intensity q = 2 N/m and force F = 6 N is applied to beam AB. It is necessary to determine the reaction of support B if length AC is equal to length AB and angle ? equals 45 degrees. The answer is 4.08.

Solution to problem 2.4.6 from the collection of Kepe O..

This digital product is a solution to problem 2.4.6 from a collection of problems in physics, authored by Kepe O..

The solution involves determining the reaction of support B of beam AB, which is subject to a distributed load of intensity q = 2 N/m and force F = 6 N. Length AC is equal to length AB, and angle ? equals 45 degrees.

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Solution to problem 2.4.6 from the collection of Kepe O.?. consists in determining the reaction of support B of beam AB under the action of a distributed load of intensity q = 2 N/m and force F = 6 N. The following conditions are given: length AC is equal to length AB, and the angle between beam AB and the horizontal plane is 45 degrees.

To solve the problem, it is necessary to use the principles of mechanics, namely, the balance of the body. First you need to determine the vertical component of the force F, which is equal to Fcos(45) = 3sqrt(2) N. Then you can determine the sum of the moments of forces about point A, which should be equal to zero if the body is in equilibrium. Taking into account that the angle between the beam and the horizontal plane is 45 degrees, we can write the equation for the moment of force:

M = -Fcos(45)AC/2 + qAC^2/2 - RvAC = 0,

where Rv is the reaction of support B, AC is the length of the beam.

Having solved this equation for Rv, we obtain the value of the support reaction B, which is equal to 4.08 N (accurate to hundredths).

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