Solution to problem 19.3.12 from the collection of Kepe O.E.

19.3.12 It is necessary to find the magnitude of the force F required to lift body 1 with mass m = 1 kg along a rough inclined plane with a given acceleration a = 1 m/s². The sliding friction coefficient on the plane is f = 0.1. (Answer: 6.75)

Solution: The sliding friction force will be directed down the inclined plane and equal to fN, where N is the support reaction force equal to mgcosθ. Here g is the acceleration of gravity, and θ is the angle of inclination of the plane to the horizon.

The sum of all forces acting on the body is equal to F - fN - mgsinθ = ma, where m is the mass of the body, and is the acceleration of the rise.

Using the equations for N and sinθ, we can express F as a function of known quantities: F = ma + fmgcosθ = ma + fmg√(1 - sin²θ)

Substituting the values, we get: F = 11 + 0,119,81√(1 - sin²θ) ≈ 6.75 (answer in Newtons)

Solution to problem 19.3.12 from the collection of Kepe O.?.

This digital product is a solution to problem 19.3.12 from the collection of problems in physics by Kepe O.?.

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This product is a solution to problem 19.3.12 from the collection “Problems in General Physics” by the author Kepe O.?. The problem is to determine the modulus of force F required to lift a body weighing 1 kg along a rough inclined plane with a sliding friction coefficient of 0.1 and a constant acceleration of 1 m/s². The solution to this problem allows you to get an answer to the question and consists of mathematical calculations using mechanics formulas and the laws of physics. The answer to the problem is 6.75.

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