Solution to problem 15.7.2 from the collection of Kepe O.E.

15.7.2 Weights 1 and 2 with masses m1 = 2 kg and m2 = 1 kg are suspended from the ends of a flexible thread thrown over a block. Determine the speed of load 1 at the time when it dropped to a height h = 3 m. The movement of loads begins from a state of rest. (Answer 4.43)

Consider a system consisting of two masses m1 = 2 kg and m2 = 1 kg, suspended from the ends of a flexible thread thrown over a block. At the initial stage, the system is at rest.

After load 1 dropped to a height h = 3 m, its potential energy decreased by m1gh, where g is the acceleration of gravity. This potential energy has turned into kinetic energy of the load, which is moving at speed v1.

Load 2 also began to move downwards, but we will not take its movement into account, since it does not affect the speed of load 1.

According to the law of conservation of energy, the potential energy of the system at the initial moment of time is equal to the sum of the kinetic energies of the loads at the final moment of time:

m1gh = (m1+m2)v1^2/2

From here we can express the speed of load 1:

v1 = sqrt(2m1g*h/(m1+m2))

Substituting the values, we get:

v1 = sqrt(229.8*3/(2+1)) ≈ 4.43 m/s

Solution to problem 15.7.2 from the collection of Kepe O.?.

This digital product is a solution to problem 15.7.2 from the collection of problems in physics by Kepe O.?. The solution to this problem involves determining the speed of load 1 suspended from the end of a flexible thread thrown over a block.

This product provides a detailed solution to the problem with a step-by-step explanation of each action, as well as justification of the applied formulas and laws of physics.

Beautiful html design of the product allows the reader to conveniently navigate the text and quickly find the necessary formulas and calculations.

By purchasing this digital product, you receive useful material for preparing for exams or Olympiads in physics, as well as for improving your knowledge in the field of physics.

Digital product "Solution to problem 15.7.2 from the collection of Kepe O.?." represents a detailed solution to a physical problem associated with determining the speed of a load 1 suspended from the end of a flexible thread thrown over a block. The problem considers a system consisting of two masses m1 = 2 kg and m2 = 1 kg, suspended from the ends of a flexible thread thrown over a block. At the initial stage, the system is at rest. After load 1 dropped to a height h = 3 m, its potential energy decreased by m1gh, where g is the acceleration of gravity. This potential energy has turned into kinetic energy of the load, which is moving at speed v1. Load 2 also began to move downwards, but its movement does not affect the speed of load 1.

This product provides a step-by-step explanation of each action, as well as a rationale for the applied formulas and laws of physics. Beautiful html design of the product allows the reader to conveniently navigate the text and quickly find the necessary formulas and calculations.

By purchasing this digital product, you receive useful material for preparing for exams or Olympiads in physics, as well as for improving your knowledge in the field of physics. Answer to problem 15.7.2 from the collection of Kepe O.?. is 4.43 m/s.

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This product is a solution to problem 15.7.2 from the collection of Kepe O.?. The problem is to determine the speed of load 1 at the moment of time when it dropped to a height h = 3 m. Weights 1 and 2 with masses m1 = 2 kg and m2 = 1 kg are suspended from the ends of a flexible thread thrown over a block. The movement of goods begins from a state of rest. The answer to the problem is 4.43.

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