When braking, a disk rotating around axis O is pressed against two brake pads with forces F1 = F2 = 100 N. It is necessary to calculate the work of sliding friction forces if the disk has a radius r = 0.1 m and goes through 10 revolutions. The sliding friction coefficient of the brake pad on the disc is f = 0.3. The answer to the problem is -377.
This digital product is a solution to problem 15.1.10 from the collection of Kepe O.?. in physics. The solution is presented in electronic form and is intended for students, teachers and anyone interested in physics.
The problem considers the braking of a disk of radius r = 0.1 m using two brake pads with forces F1 = F2 = 100 N and a sliding friction coefficient of the brake pad on the disc f = 0.3. The solution will allow us to calculate the work of sliding friction forces when the disk brakes for 10 revolutions.
The digital product is presented in the form of a beautifully designed html file that is easy to open and view on any device. By purchasing this digital product, you get a convenient and affordable way to familiarize yourself with the solution to the problem and improve your knowledge in the field of physics.
The digital product is a solution to problem 15.1.10 from the collection of Kepe O.?. in physics. The problem considers the braking of a disk of radius r = 0.1 m using two brake pads with forces F1 = F2 = 100 N and a sliding friction coefficient of the brake pad on the disc f = 0.3. The problem requires calculating the work of sliding friction forces when the disk brakes for 10 revolutions. The solution is presented in the form of a beautifully designed html file that is easy to open and view on any device. This digital product is intended for students, teachers and anyone interested in physics who want to improve their knowledge in this area. By purchasing this product, you get a convenient and affordable way to familiarize yourself with the solution to the problem and improve your knowledge in the field of physics. The answer to the problem is -377.
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The product in this case is the solution to problem 15.1.10 from the collection of Kepe O.?.
The task is to calculate the work of sliding friction forces when braking a disk of radius r = 0.1 m for 10 revolutions. To do this, it is necessary to take into account the forces F1 and F2, equal to 100 N, with which two brake pads are pressed against the disc, as well as the sliding friction coefficient of the brake pad on the disc f = 0.3.
The problem can be solved as follows:
Find the total work of friction forces for 10 revolutions of the disk. To do this, we use the formula for the work of force: A = F * s, where F is the sliding friction force, s is the path traveled by the point of application of the force. The path s traversed by the point of application of force in 10 revolutions is equal to 2 * pi * r * 10, where r is the radius of the disk. The sliding friction force is equal to F = f * N, where N is the normal reaction force, equal to the sum of the forces F1 and F2. Thus, the total work of friction forces will be equal to A = F * s = f * N * 2 * pi * r * 10.
Substitute the known values into the formula and solve the equation: A = 0.3 * (100 + 100) * 2 * pi * 0.1 * 10 = -377 J.
Answer: the work of sliding friction forces when braking a disk of radius r = 0.1 m for 10 revolutions is equal to -377 J.
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