Solution to problem 15.2.6 from the collection of Kepe O.E.

Problem 15.2.6 describes the motion of a material point with mass m = 0.2 kg. It moves along a horizontal platform at a distance R = 1 m from the axis of rotation with a speed vr = 3 m/s relative to the platform, which in turn rotates with an angular velocity ? = 2 rad/s. It is necessary to determine the kinetic energy of a given material point.

To solve the problem, we use the formula for calculating kinetic energy:

E = (mv^2) / 2,

where m is the mass of the material point, v is its speed.

First, let's find the speed of the material point relative to the center of rotation of the platform. To do this, we use the formula for linear speed:

v = ?r,

Where ? - angular velocity of rotation of the platform, r - distance from the axis of rotation to the material point.

Thus, the speed of the material point relative to the center of rotation is equal to:

v' = ?r = 2*1 = 2 m/s.

Then we find the speed of the material point relative to the earth, taking into account its speed relative to the platform:

v = v' + vr = 2 + 3 = 5 м/с.

Finally, let's calculate the kinetic energy of a material point:

E = (0.2*5^2) / 2 = 2.5 J.

Thus, the kinetic energy of a material point is 2.5 J.

Solution to problem 15.2.6 from the collection of Kepe O.?.

This digital product is a complete and detailed solution to problem 15.2.6 from the collection of problems in physics by Kepe O.?. This product is intended for schoolchildren, students and anyone who studies physics and wants to deepen their knowledge in this area.

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This product is a complete and detailed solution to problem 15.2.6 from the collection of problems in physics by Kepe O.?.

The problem describes the motion of a material point with mass m = 0.2 kg moving along a horizontal platform at a distance R = 1 m from the axis of rotation with a speed vr = 3 m/s relative to the platform, which in turn rotates with an angular velocity ? = 2 rad/s. It is necessary to determine the kinetic energy of a given material point.

To solve the problem, a formula is used to calculate kinetic energy: E = (mv^2) / 2, where m is the mass of the material point, v is its speed. First, the velocity of the material point relative to the center of rotation of the platform is found using the formula for linear velocity: v = ?r, where ? - angular velocity of rotation of the platform, r - distance from the axis of rotation to the material point.

Thus, the speed of the material point relative to the center of rotation is equal to: v' = ?r = 2*1 = 2 m/s. Then the speed of the material point relative to the ground is found, taking into account its speed relative to the platform: v = v' + vr = 2 + 3 = 5 m/s.

Finally, the kinetic energy of the material point is calculated: E = (0.2*5^2) / 2 = 2.5 J.

By purchasing this product, you get access to a detailed description of the solution to the problem, which is presented in the form of a beautiful HTML document. The solution to the problem was carried out by a professional teacher, which guarantees its high quality and correctness.

This digital product will be useful for schoolchildren, students and anyone who studies physics and wants to deepen their knowledge in this area. This product will help you prepare for exams, complete homework and tests. In addition, you get the opportunity to ask questions to the author of the solution if you have any questions or ambiguities. Your learning and understanding of the material is our main goal!

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The product in this case is the solution to problem 15.2.6 from the collection of Kepe O.?.

The problem considers the movement of a material point with a mass of 0.2 kg on a horizontal platform at a distance of 1 m from the axis of rotation. The platform rotates with an angular velocity of 2 rad/s, and the relative speed of the material point is 3 m/s.

It is necessary to find the kinetic energy of a material point.

To solve the problem, you can use the formula for kinetic energy: E = (mv^2) / 2, where m is the mass of the material point, v is its speed.

First you need to find the speed of the material point relative to the center of rotation of the platform. To do this, you can use the formula for speed on a circle: v = ?r, where ? - angular velocity of rotation of the platform, r - distance from the center of rotation to the material point.

v = 2 rad/s * 1 m = 2 m/s

Then you can find the speed of a material point relative to the ground using the formula for adding velocities:

v' = sqrt((v + vr)^2) = sqrt((2 m/s + 3 m/s)^2) = 5 m/s

Now we can calculate the kinetic energy of a material point:

E = (mv'^2) / 2 = (0.2 kg * (5 m/s)^2) / 2 = 2.5 J

Thus, the kinetic energy of a material point is 2.5 J.

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