Solution to problem 11.4.6 from the collection of Kepe O.E.

11.4.6 The tube rotates around the OO1 axis with an angular velocity ω = 1.5 rad/s. Ball M moves along the tube according to the law M0M = 4 t. Find the Coriolis acceleration modulus of the ball. (Answer 12)

Answer:

The Coriolis acceleration for a ball moving along a curved path can be found using the formula:

К = 2ω × V,

where ω is the angular velocity of rotation of the tube, and V is the speed of the ball.

Let's find the speed of the ball:

V = d(M0M)/dt = 4 м/с.

Substituting the values ​​into the formula for the Coriolis acceleration, we get:

K = 2 × 1.5 rad/s × 4 m/s = 12 m/s².

Answer: 12.

Solution to problem 11.4.6 from the collection of Kepe O..

that digital product is the solution to one of the problems from the collection “Problems in General Physics” by the author O.. Kepe. The solution is presented in HTML format and is designed beautifully and is easy to read.

Problem 11.4.6 describes the motion of a ball along a curved path when the tube along which the ball moves rotates around an axis with a certain angular velocity. Solving a problem includes a detailed description of the solution process, formulas and calculations, as well as the correct answer to the problem.

By purchasing this digital product, you can use it to prepare for exams, study physics on your own, or simply gain interest in this science.

The digital product you are purchasing is a solution to problem 11.4.6 from the collection “Problems in General Physics” by author O.?. Kepe in HTML format.

The problem is that the tube rotates around an axis with an angular velocity ω = 1.5 rad/s, and the ball M moves along the tube according to the law M0M = 4 t. It is necessary to find the Coriolis acceleration modulus of the ball.

Solving a problem includes a detailed description of the solution process, formulas and calculations, as well as the correct answer to the problem. The Coriolis acceleration for a ball moving along a curved path can be found by the formula: K = 2ω × V, where ω is the angular velocity of rotation of the tube, and V is the speed of the ball.

The speed of the ball can be found by differentiating the law of motion M0M = 4 t with respect to time, which gives V = d(M0M)/dt = 4 m/s.

Substituting the values ​​into the formula for Coriolis acceleration, we get: K = 2 × 1.5 rad/s × 4 m/s = 12 m/s².

By purchasing this digital product, you will receive useful material for studying for exams or studying physics on your own, and also learn how to solve problems related to Coriolis acceleration.

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The product is the solution to problem 11.4.6 from the collection of problems in physics by the author Kepe O.?.

This problem considers the movement of a ball along a tube that rotates around the OO1 axis with an angular velocity ω=1.5 rad/s. The trajectory of the ball is given by the law М0М=4t. It is required to find the Coriolis acceleration modulus of the ball.

The solution to this problem consists of the following steps. The first step is to find the speed of the ball relative to the ground. To do this, use the expression for the speed of a point moving along a rotating tube. Then the Coriolis acceleration is found, which is defined as the product of the angular velocity of rotation of the tube and the velocity vector of the ball relative to the ground. Finally, the Coriolis acceleration modulus of the ball is found using known values ​​of the quantities.

As a result of solving this problem, it turns out that the Coriolis acceleration modulus of the ball is equal to 12. The answer corresponds to that specified in the problem statement.

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