Solution to problem 1.2.11 from the collection of Kepe O.E.

1.2.11 Ball 1 weighing 16N and ball 2 are connected by a thread thrown over block D and kept in balance. Determine the weight of ball 2 if the angle ?= 30°. (Answer 9.24)

To solve this problem, it is necessary to use the body equilibrium condition:

ΣF = 0, where ΣF is the sum of all forces acting on the body.

In this case, two forces act on ball 2: the tension force of the thread T and the force of gravity F₂.

The tension force of the thread is directed at an angle? to the horizon:

T = F₁/sin?, where F₁ - gravity of the ball 1.

The gravity of ball 2 is directed vertically downward:

F₂ = m₂g, where m₂ - mass of the ball 2, g - acceleration of free fall.

Considering that the system is in equilibrium, the tension force of the thread should be equal to the gravity force of ball 2:

T = F₂.

Substituting expressions for T and F₂, we get:

F₁/sin? = m₂g

Expressing the mass of ball 2, we get:

m₂ = F₁/(g*sin?) = 16/(9.81*sin30°) = 9.24 N

Thus, the weight of ball 2 is 9.24 N.

Solution to problem 1.2.11 from the collection of Kepe O..

Our digital goods store presents to your attention the solution to problem 1.2.11 from the collection of Kepe O.. This digital product is intended for those who study physics and want to develop their problem-solving skills.

This problem considers two balls connected by a thread over a block and in equilibrium. The problem is to determine the weight of the second ball, provided that the angle of the thread is 30 degrees. The solution to the problem is presented in the form of detailed calculations and explanations that will help you better understand physical laws and apply them in practice.

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We present to your attention the solution to problem 1.2.11 from the collection of Kepe O.?.

Given: Ball weight 1 - 16 N The angle between the thread and the horizon is 30 degrees

Find: Ball weight 2

Solution: Ball 1 and ball 2 are connected by a thread over block D and are kept in balance. This means that the weight of ball 1 and the weight of ball 2 must be equal.

We can use the law of conservation of energy to find the weight of ball 2. Let's look at the forces acting on the system:

• The weight of ball 1 is directed downward and equal to 16 N
• The weight of ball 2 is directed downward and unknown
• The tension in the thread is directed upward and is equal to the weight of both balls

So we can write the equation:

16 N + ball weight 2 = thread tension

We can express the thread tension from geometric considerations:

thread tension = ball weight 1 / sin ?

Where ? - the angle between the thread and the horizon, which is 30 degrees.

Now we can write the final equation:

16 N + weight of ball 2 = (16 N / sin 30°)

Solving this equation, we get:

ball weight 2 = (16 N / sin 30°) - 16 N ≈ 9.24 N

Thus, the weight of ball 2 is approximately 9.24 N.

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