Solution K1-30 (Figure K1.3 condition 0 S.M. Targ 1989)

The solution to problem K1-30, which is represented by two subtasks K1a and K1b, is shown in Figure K1.3 in condition 0 S.M. Targ 1989 edition. The first subtask K1a is to determine the equation of the trajectory of point B moving in the xy plane with coordinates x = f1(t) and y = f2(t), where t is measured in seconds, and x and y are measured in centimeters. It is necessary to find the speed and acceleration of the point at time t1 = 1 s, as well as the tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x = f1(t) is indicated directly in the figures, and the dependence y = f2(t) is given in the table. K1 (for figures 0-2 in column 2, for figures 3-6 in column 3, for figures 7-9 in column 4). The figure number is selected according to the penultimate digit of the code, and the condition number in the table. K1 - according to the last one. The second subtask K1b is to determine the speed and acceleration of a point moving along a circular arc of radius R = 2 m according to the law s = f(t), given in table. K1 in column 5 (s - in meters, t - in seconds). It is also necessary to depict vectors v and a in the figure, assuming that the point at time t1 = 1 s is in position M, and the positive direction of reference s is from A to M.

This digital product is a solution to problem K1-30 from the textbook by S.M. Targa 1989. The product includes two subtasks K1a and K1b, which are solved on the basis of Figure K1.3 and condition 0.

In the first subtask K1a, it is necessary to determine the equation for the trajectory of point B moving in the xy plane along given coordinates x = f1(t) and y = f2(t), and also find the speed and acceleration of the point at time t1 = 1 s, as well as the tangent and normal acceleration and radius of curvature at the corresponding point of the trajectory. The second subtask K1b is to determine the speed and acceleration of a point moving along an arc of a circle of radius R = 2 m according to a given law s = f(t), as well as to depict vectors v and a in the figure at time t1 = 1 s.

The design of this product is made in a beautiful html format, which allows you to conveniently view and study the material. This digital product will be useful to students and teachers involved in physics and mathematics, as well as anyone who needs to solve the K1-30 problem.

Solution K1-30 is a digital product that contains a solution to two subtasks K1a and K1b, based on Figure K1.3 from condition 0 S.M. Targa 1989 edition.

In the first subtask K1a, it is necessary to find the equation for the trajectory of point B moving in the xy plane with coordinates x = f1(t) and y = f2(t), where t is measured in seconds, and x and y are measured in centimeters. You also need to find the speed and acceleration of the point at time t1 = 1 s, as well as the tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence x = f1(t) is indicated directly in the figures, and the dependence y = f2(t) is given in table K1 (for figures 0-2 in column 2, for figures 3-6 in column 3, for figures 7-9 in column 4).

In the second subtask K1b, it is necessary to determine the speed and acceleration of a point moving along an arc of a circle of radius R = 2 m according to the law s = f(t), given in table K1 in column 5 (s - in meters, t - in seconds). You also need to depict in the figure the vectors v and a at the time t1 = 1 s, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

This digital product is designed in a beautiful html format, which allows you to conveniently view and study the material. It will be useful to students and teachers involved in physics and mathematics, as well as to anyone who needs to solve problem K1-30.

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Solution K1-30 is a task that consists of two subtasks K1a and K1b. In problem K1a, it is necessary to find the equation for the trajectory of point B moving in the xy plane according to the law x = f1(t), y = f2(t), where x and y are expressed in centimeters, t - in seconds. For the moment of time t1 = 1 s, it is necessary to determine the speed and acceleration of the point, as well as its tangential and normal accelerations and the radius of curvature at the corresponding point of the trajectory. The dependence y = f2(t) is given in table. K1, and the dependence x = f1(t) is indicated directly in the figures. The figure number is selected according to the penultimate digit of the code, and the condition number in the table. K1 - according to the last one.

In problem K1b, a point moves along a circular arc of radius R = 2 m according to the law s = f(t), given in table. K1 in column 5 (s - in meters, t - in seconds), where s = AM is the distance of a point from some origin A, measured along the arc of a circle. It is necessary to determine the speed and acceleration of the point at time t1 = 1 s. In the figure, it is necessary to depict the vectors v and a, assuming that the point at this moment is in position M, and the positive direction of reference s is from A to M.

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Peculiarities:

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This product offers a unique solution to the problem from the textbook S.M. Targa 1989, which makes it indispensable for preparing for exams and tests.

Figure K1.3 condition 0 is a key element of the solution, and thanks to this digital product, you can easily understand the intricacies of the problem.

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