We are looking for the specific heat capacity at constant volume for a gas mixture whose kilomolar mass is 22 kg and the specific heat capacity ratio is 1.395. The solution to problem No. 20395 will be given below with a brief record of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer. If you have any questions about the solution, do not hesitate to write, I will try to help.
So, let's solve the problem. From the problem conditions it is known that the mass of a kilomole of the gas mixture is 22 kg, which means that one kilomole contains 22 kg of gas.
The specific heat capacity at constant volume for a gas mixture can be calculated using the formula: Cv = (f/2)R / (f/2 - 1), where Cv is the specific heat capacity at constant volume, R is the universal gas constant, f is the degree of freedom .
For a gas mixture, the degree of freedom can be calculated using the formula: f = (n1f1 + n2f2 + ... + nk*fk) / (n1 + n2 + ... + nk), where n1, n2, ..., nk is the number of moles of each gas in the mixture, f1, f2, ..., fk - degrees of freedom of each gas.
Thus, we can calculate the degree of freedom of the gas mixture: f = (13/2 + 15/2) / (1 + 1) = 4/2 = 2.
The universal gas constant R is 8.31 J/(mol*K).
Now we can calculate the specific heat capacity at constant volume for a gas mixture: Cv = (f/2)R / (f/2 - 1) = (2/2)8.31 / (2/2 - 1) = 20.775 J/(kgTO).
Answer: the specific heat capacity at constant volume for a gas mixture whose kilomolar mass is 22 kg and the specific heat capacity ratio is 1.395 is 20.775 J/(kg*K).
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This digital product provides a detailed solution to a physics problem that requires calculating the specific heat capacity at constant volume for a gas mixture. The solution includes a brief record of the conditions, formulas and laws used in the calculations, the derivation of the calculation formula and the answer to the problem.
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This digital product is a detailed solution to the physical problem of finding the specific heat capacity at constant volume for a gas mixture whose kilomolar mass is 22 kg and the specific heat ratio is 1.395. The solution includes a brief recording of the conditions of the problem, formulas and laws used in the calculations, the derivation of the calculation formula and the answer to the problem.
This digital product will be useful to students, teachers and anyone interested in physics, as well as those preparing to take exams and tests in this discipline.
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The price of this digital product is 99 rubles. By purchasing this product, you gain access to useful information that will help you better understand the physics problem and its solution.
The specific heat capacity at constant volume for a gas mixture whose kilomolar mass is 22 kg and the specific heat capacity ratio is 1.395 is 20.775 J/(kg*K). This digital product is a detailed solution to the physical problem No. 20395, including a brief recording of the conditions, formulas and laws used in the calculations, the derivation of the calculation formula and the answer to the problem. By purchasing this product you will gain a thorough understanding of the solution to this problem and will be able to apply it to your own calculations. Presenting the solution in HTML format makes it more attractive and easier to read. The cost of the product is 99 rubles. If you have any questions about solving a problem, do not hesitate to ask for help.
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For a gas mixture with a kilomolar mass of 22 kg and a specific heat ratio of 1.395, we need to find the specific heat at constant volume.
To solve this problem, you can use Mayer's formula:
Cv = (f / 2) * R
where Cv is the specific heat capacity at constant volume, f is the degree of freedom of gas molecules (for a gas mixture f = 7/2), R is the universal gas constant.
The value of the universal gas constant R can be found using the formula:
R = 8.314 / kilomolar mass of gas
where 8.314 is the universal gas constant in joules per mole and kelvin, kilomolar mass of gas is the mass of one kilomole of gas.
Thus, to find the specific heat capacity at constant volume for a given gas mixture, the following steps must be followed:
Find the universal gas constant R: R = 8.314 / 22 = 0.3788 J / (kg * K)
Substitute the value of R and the degree of freedom f into Mayer’s formula: Cv = (7/2) * 0.3788 = 1.325 J / (kg * K)
Thus, the specific heat capacity at constant volume for a given gas mixture is 1.325 J/(kg * K).
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