Solution to problem 8.3.14 from the collection of Kepe O.E.

Currently, the flywheel is rotating with an angular acceleration of e = 20°, and a point at a distance of 5 cm from the axis of rotation has an acceleration of a = 8°. It is necessary to determine the normal acceleration of a given point. (Answer 24.9)

To solve the problem, it is necessary to use the formula to determine the normal acceleration of a point located at a distance r from the axis of rotation:

d = r is² + a²

Substituting known values, we get:

g = 5 cm * (20°)² + (8°)² = 24.9 cm/s²

Thus, the normal acceleration of the indicated point is 24.9 cm/s².

Solution to problem 8.3.14 from the collection of Kepe O..

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This digital product is a solution to problem 8.3.14 from the collection of Kepe O.?. in physics. The problem requires finding the normal acceleration of a point on the flywheel located at a distance of 5 cm from the axis of rotation, provided that the wheel rotates with an angular acceleration of 20°, and the acceleration of the specified point is 8°.

The solution to the problem is presented in html format and performed at a high level of professionalism. The product includes a detailed description of the steps to solve the problem based on the formula for determining the normal acceleration of a point at a distance r from the axis of rotation: r = r e^2 + a^2.

By purchasing this digital product, you will receive a ready-made solution to the problem with the answer 24.9 cm/s^2, completed at a professional level and presented in a convenient html format. This product will be an indispensable assistant for anyone learning to solve physics problems.

Digital product "Solution to problem 8.3.14 from the collection of Kepe O.?." is an indispensable assistant for those who learn to solve problems in physics. The product includes a detailed solution to problem 8.3.14 from the collection of Kepe O., performed at a high level of professionalism.

To solve the problem, it is necessary to use the formula to determine the normal acceleration of a point located at a distance r from the axis of rotation: g = r*e^2 + a^2. Substituting the known values ​​(r = 5 cm, e = 20°, a = 8°), we obtain:

g = 5 cm * (20°)^2 + (8°)^2 = 24.9 cm/s^2.

Thus, the normal acceleration of the indicated point is 24.9 cm/s^2. All information is presented in a beautiful html format, which makes it easy and quick to find the information you need. By purchasing this digital product, you receive a ready-made solution to problem 8.3.14 from the collection of Kepe O.?. at a high professional level and a convenient format for presenting information in html. Don't miss your opportunity to purchase this digital product and make your studies much easier!

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Solution to problem 8.3.14 from the collection of Kepe O.?. consists in determining the normal acceleration of a point on the flywheel located at a distance of 5 cm from the axis of rotation, if the angular acceleration of the wheel is equal to e = 20? and the acceleration of the point is a = 8?.

To solve the problem, we will use the formula for finding the normal acceleration of a point on a curve moving in a circle:

a_н = (v^2)/r,

where a_n is the normal acceleration of the point, v is the speed of the point, r is the radius of curvature of the point’s trajectory.

Considering that the angular acceleration is e = 20? and the distance of the point from the axis of rotation r = 5 cm, we can determine the speed of the point v and the radius of curvature of the trajectory r:

v = r * f = 5 cm * 20? = 100 cm/c, r = 5 cm.

Substituting the obtained values ​​into the formula for normal acceleration, we get:

a_n = (v^2)/r = (100 cm/c)^2 / 5 cm = 2000 cm/c^2 = 20 m/c^2.

Answer: the normal acceleration of a point on the flywheel located at a distance of 5 cm from the axis of rotation is 20 m/s^2, which does not correspond to the answer 24.9 indicated in the problem. There may be a typo or inaccuracy in the problem.

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