Solution of problem 2.5.3 from the collection of Kepe O.E.

Solution to problem 2.5.3 from the collection of Kepe O..

that digital product is the solution to one of the problems from the collection “Problems in General Physics” by the author Kepe O.. that problem (2.5.3) relates to the topic “Dynamics of a material point and a system of material points.”

In this solution you will find a detailed description and formulas necessary to determine the minimum weight of body 1 at which it begins to slide down the plane DE.

The design of this page is made in a beautiful and easy-to-read style that will help you quickly and easily master the material and solve the problem.

By purchasing this digital product, you get access to a high-quality and useful solution to the problem that will help you improve your knowledge in the field of physics and prepare for exams or tests.

The offered product is a solution to problem 2.5.3 from the collection “Problems in General Physics” by the author Kepe O.?. The problem relates to the topic "Dynamics of a material point and a system of material points." In this solution you will find a detailed description and formulas that will allow you to determine the minimum weight of body 1 at which it begins to slide down the plane DE. The sliding friction coefficient between body 1 and plane DE is 0.2, and the weight of load 2 is 320 N. The page design is made in a beautiful and easy-to-read style, which will allow you to quickly and easily master the material and solve the problem. By purchasing this digital product, you will get access to a high-quality and useful solution to the problem that will help you improve your knowledge in the field of physics and prepare for exams or tests. The answer to the problem is 979.

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Solution to problem 2.5.3 from the collection of Kepe O.?. consists in determining the minimum weight of body 1 at which it will begin to slide down the plane DE. To do this, it is necessary to use known data: the weight of load 2 is 320N, and the sliding friction coefficient between body 1 and plane DE is 0.2.

To solve the problem, you can use the friction force formula: Ftr = μN, where μ is the friction coefficient, N is the normal force, Ftr is the friction force. The normal force is equal to the weight of the body, that is, N = mg, where m is the mass of the body, g is the acceleration of gravity.

Thus, the friction force is equal to Ftr = μmg, and the force acting on body 1 is equal to the force of gravity, i.e. m1g.

In the problem statement, it is necessary to find the smallest mass of body 1 at which it will begin to slide down the plane DE. This will happen at the moment when the friction force is equal to the force of gravity, i.e. μmg = m1g.

Expressing the mass of body 1 from this equation, we obtain: m1 = μm. It is also necessary to take into account the weight of load 2, which creates an additional force of gravity equal to 320N.

Thus, the required mass of body 1 is equal to: m1 = μm + m2 = μFн/ g + m2, where Fн is the normal force equal to the weight of body 1 and load 2, i.e. Fн = (m1 + m2)g.

Substituting the known values, we get: m1 = (0.2*(m1 + m2))/g + m2. Solving this equation for m1, we get: m1 = 979 kg.

Thus, the smallest weight of body 1 at which it begins to slide down the plane DE is 979 kg.

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