A quartz plate was placed between the crossed polaroids.

Between the polaroids, located perpendicular to each other, a quartz plate was inserted, which was cut across the optical axis. In order for light with a wavelength of lambda = 0.5 μm to be extinguished, the analyzer had to be rotated at an angle = 22°. If the rotation constant of quartz for this wavelength is known to be 29.7°/mm, then what is the thickness of the plate?

The key product of the digital store is the digital content, which has been designed in an attractive HTML design. The content is a unique description of an optical experiment in which a quartz plate was placed between crossed polaroids. This experiment may be of interest to both beginners and experienced physicists, as well as people interested in optics. Using this content, users can learn how to rotate the analyzer 22° to extinguish light at a wavelength of 0.5 µm and calculate the wafer thickness using the quartz rotation constant, which is 29.7°/mm for this wavelength. All information is presented in an attractive design using HTML code, which makes it easy to view and understand the material.

Product description:

The offered product is digital content in HTML format containing a unique description of an optical experiment. In the experiment, a quartz plate cut across the optical axis was placed between crossed polaroids. In order to extinguish light with a wavelength of lambda = 0.5 μm, it was necessary to rotate the analyzer at an angle = 22°. The rotation constant of quartz for this wavelength is known to be 29.7°/mm.

This content may be of interest to both beginners and experienced physicists, as well as people interested in optics. It is presented in an attractive design using HTML code, making the material easy to view and understand. The content provides a detailed description of the experimental conditions, formulas, laws and calculations necessary to calculate the thickness of the plate.

If you have any questions about solving a problem, you can contact the content author for further assistance.

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The product described in this text is a quartz slab cut across the optical axis and placed between crossed Polaroids. This quartz plate has a rotation constant for a wavelength lambda = 0.5 µm equal to 29.7 °/mm.

In order to extinguish light with a given wavelength, it is necessary to rotate the analyzer at an angle = 22°. From this information, one can obtain the value of the light path difference between crossed polaroids, which is equal to the thickness of the quartz plate multiplied by the rotation constant of the quartz for a given wavelength.

Thus, to find the thickness of the plate, you need to use the formula:

d = (2k + 1) * lambda / (4 * n),

where k is an integer, lambda is the wavelength of light, n is the refractive index of quartz.

In this case, since the light is extinguished, the difference in the light path between the crossed polaroids is equal to half the wavelength, that is, lambda/2. The refractive index of quartz for a given wavelength can be found from tables or using the values ​​given in the problem.

Substituting all known values ​​into the formula, we get:

d = (2k + 1) * lambda / (4 * n) = (2 * 0 + 1) * 0.5 μm / (4 * n) = 0.125 μm / n.

Thus, to find the thickness of the plate, it is necessary to calculate the value of the refractive index of quartz for a wavelength of 0.5 microns and substitute it into this formula. The answer can be expressed in micrometers.

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