A thin wire (with insulation) forms a flat spiral of

Given a thin wire with insulation, which forms a flat spiral of N = 100 tightly adjacent turns, through which a current I = 8 mA flows. The radius of the inner turn is a = 50 mm, and the radius of the outer turn is b = 100 mm. It is necessary to determine the magnetic field induction B at the center of the spiral.

Answer:

Let's find the average radius of the spiral:

r = (a + b) / 2 = (50 mm + 100 mm) / 2 = 75 mm = 0.075 m

Let's find the cross-sectional area of ​​the wire:

S = πr^2 = π(0.075 м)^2 ≈ 0.0177 м^2

Let's find the magnetic constant:

μ0 = 4π * 10^-7 Gn/m

We use the formula to calculate the magnetic induction in the center of a circular contour:

B = (μ0 * I * N) / (2 * r)

Let's substitute the known values ​​and calculate:

B = (4π * 10^-7 H/m * 8 * 10^-3 A * 100) / (2 * 0.075 m) ≈ 0.0423 T

Answer: the magnetic field induction at the center of the spiral is 0.0423 Tesla.

Task №31313

Given a thin wire with insulation, which forms a flat spiral of N = 100 tightly adjacent turns, through which a current I = 8 mA flows. The radius of the inner turn is a = 50 mm, and the radius of the outer turn is b = 100 mm. It is necessary to determine the magnetic field induction B at the center of the spiral.

Answer:

Let's find the average radius of the spiral:

r = (a + b) / 2 = (50 mm + 100 mm) / 2 = 75 mm = 0.075 m

Let's find the cross-sectional area of ​​the wire:

S = πr^2 = π(0.075 м)^2 ≈ 0.0177 м^2

Let's find the magnetic constant:

μ0 = 4π * 10^-7 Gn/m

We use the formula to calculate the magnetic induction in the center of a circular contour:

B = (μ0 * I * N) / (2 * r)

Let's substitute the known values ​​and calculate:

B = (4π * 10^-7 H/m * 8 * 10^-3 A * 100) / (2 * 0.075 m) ≈ 0.0423 T

Answer: the magnetic field induction at the center of the spiral is 0.0423 Tesla.

Cargo code: 12345678

Thin wire with insulation to create a flat spiral

This thin insulated wire is an excellent choice for creating a flat spiral. It forms a spiral of 100 tightly fitting turns, through which a current of up to 8 mA can flow. The turns have radii of 50 mm and 100 mm for the inner and outer turns, respectively.

The wire is made of high-quality materials and has high wear resistance, which ensures long service life. It is easy to manipulate and is ideal for creating various electrical devices and experiments in the field of electromagnetism.

Buy this thin insulated wire and create amazing devices right at home!

Price: 499 rub.

Cargo code: 12345678

Product Description: Thin insulated wire designed to create a flat spiral of 100 tightly fitting turns. The wire is highly wear-resistant and easy to handle. A current of up to 8 mA can flow through the wire. The radius of the inner turn is 50 mm, and the radius of the outer turn is 100 mm. Using this wire, you can create various electrical devices and conduct experiments in the field of electromagnetism.

To determine the magnetic field induction B at the center of the spiral, the formula is used:

B = (μ0 * I * N) / (2 * r),

where μ0 is the magnetic constant, I is the current, N is the number of turns, r is the average radius of the spiral.

Substituting known values, we get:

B = (4π * 10^-7 H/m * 8 * 10^-3 A * 100) / (2 * 0.075 m) ≈ 0.0423 T.

Answer: the magnetic field induction at the center of the spiral is 0.0423 Tesla.

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thin insulated wire forming a flat spiral of 100 tightly fitting turns. This wire is used to create a magnetic field in the center of the spiral. The current passing through the wire is 8 mA. The radius of the inner turn is 50 mm, and the radius of the outer turn is 100 mm. To determine the magnetic field induction at the center of the spiral, the formula is used:

B = (μ0 * N * I) / (2 * R)

where B is the desired magnetic field induction, μ0 is the magnetic constant, N is the number of turns, I is the current strength in the wire, R is the radius of the center line of the spiral (R = (a + b) / 2).

For a given spiral, the R value is:

R = (50 mm + 100 mm) / 2 = 75 mm

Thus, substituting known values ​​into the formula, we get:

B = (4π * 10^-7 * 100 * 8 * 10^-3) / (2 * 75 * 10^-3) ≈ 0.067 Тл

Answer: The magnetic field induction at the center of the spiral is approximately 0.067 Tesla.

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