Will be dark or light in reflected monochromatic

Let's consider the problem of what color a soap film (n = 4/3) with a thickness of d=3.375 μm will have at normal incidence of rays with a wavelength of 600 nm.

Using the relationship to determine the path difference between the rays passing through the soap film, we obtain:

δ = 2ndμ = 2 * 3.375 * 10^-6 * (4/3) = 9 * 10^-6 m

where μ is the refractive index of the film substance, and n is the refractive index of air.

In order to determine the color, it is necessary to divide the path difference by the wavelength:

d/l = 9 * 10^-6 / 600 * 10^-9 = 15

The resulting number is an integer, therefore, we will observe an interference pattern of dark and light stripes against a green background. Film thickness can also be calculated using this formula:

d = (m + 1/2)l/2m

where m is an integer indicating the order of interference.

Answer: a soap film with a thickness of d=3.375 µm under normal incidence of rays with a wavelength of 600 nm will have an interference pattern of dark and light stripes against a green background.

Problem 40517. Detailed solution with a brief record of the conditions, formulas and laws used in the solution, derivation of the calculation formula and answer. If you have any questions regarding the solution, please write. We'll try to help.

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Product description:

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