Solution of problem 2.5.2 from the collection of Kepe O.E.

2.5.2

In order for body 1 weighing 200 N to begin sliding along a horizontal plane with a sliding friction coefficient f = 0.2, it is necessary to determine the minimum weight of body 2.

Answer: 40.0

Thus, for body 1 to begin sliding along a horizontal plane, it is necessary that the weight of body 2 be at least 40.0 N.

Solution to problem 2.5.2 from the collection of Kepe O..

that digital product is the solution to problem 2.5.2 from Kepe O..’s collection on physics. It provides a detailed description of how to find the smallest weight of body 2 required for body 1 weighing 200 N to begin sliding along a horizontal plane with a sliding friction coefficient f = 0.2.

In this solution you will find a step-by-step explanation of the method for solving the problem, as well as calculations and an answer to the question. Beautiful html design will make reading the solution more convenient and enjoyable.

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Solution to problem 2.5.2 from the collection of Kepe O.?. in physics is a digital product that contains a detailed description of the method for solving the problem. In this solution you will find a step-by-step explanation of how to find the smallest weight of body 2 required for body 1 weighing 200 N to begin sliding on a horizontal plane with a sliding friction coefficient f = 0.2.

The solution includes calculations and an answer to the question, as well as a beautiful design in html format, which makes reading the solution more convenient and enjoyable. This product will be useful for physics students and teachers who want to better understand and assimilate the material, as well as for anyone interested in solving physics problems. In this problem, it is necessary to determine the minimum weight of body 2 so that body 1 begins to slide along a horizontal plane with a sliding friction coefficient f = 0.2. The answer to this question is 40.0 N.

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Solution to problem 2.5.2 from the collection of Kepe O.?. consists in determining the minimum weight of body 2 at which body 1 will begin to slide along a horizontal plane if the sliding friction coefficient f is equal to 0.2 and body 1 has a weight of 200 N.

To solve the problem, it is necessary to use the equilibrium condition of the body, according to which the sum of all forces acting on the body is equal to zero. The sliding friction force acting on body 1 is equal to f*N, where N is the normal force acting on the body from the supporting surface. In this case, N is equal to the weight of body 1.

Thus, the sum of forces acting on body 1 is equal to:

F = N - f*N = N(1-f) = 200(1-0.2) = 160 Н.

In order for body 1 to begin sliding along a horizontal plane, it is necessary that the sliding friction force reaches the value F, that is, f*N = 160 N. Solving this equation for the weight of body 2, we obtain:

N2 = F/f = 160/0.2 = 800 Н.

Thus, the smallest weight of body 2 at which body 1 will begin to slide along the horizontal plane is 800 - 200 = 600 N, which corresponds to 60.0 kg or 40.0 pounds.

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