Solution to problem 14.1.18 from the collection of Kepe O.E.

14.1.18. Solution tasks

Let us consider a system consisting of body 1 with a mass of 4 kg and a homogeneous rod 2 with a mass of 2 kg and length l = 0.6 m. Initially, the system was at rest. When the rod is lowered under the influence of gravity, it will take a vertical position.

Since the system was at rest, its potential energy at the initial moment is zero. When the rod lowers to a vertical position, its potential energy will reach its maximum value, and the potential energy of body 1 will decrease by an amount equal to the work done by gravity when the body moves a distance h.

From the law of conservation of energy we obtain:

m1gh = ΔE = -m1gh,

where m1 is the mass of body 1, g is the acceleration of gravity, h is the height to which body 1 rose.

From here we get:

h = 0.

Thus, body 1 will not move in the horizontal direction. Answer: 0.1.

Solution to problem 14.1.18 from the collection of Kepe O.?.

We present to your attention a digital product - a solution to problem 14.1.18 from the collection of Kepe O.?. in physics. This product is suitable for anyone who is studying mechanics and wants to test their knowledge.

This solution takes into account all the conditions of the problem and provides the detailed steps required to achieve the correct answer. For your convenience, we have formatted the solution in Microsoft Word 2003 using the formula editor, which makes it easy to read and check each step.

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The digital product is a solution to problem 14.1.18 from the collection of Kepe O.?. in physics. In this problem, we consider a system consisting of body 1 with a mass of 4 kg and a homogeneous rod 2 with a mass of 2 kg and length l = 0.6 m. At the initial moment, the system was at rest. When the rod is lowered under the influence of gravity, it will take a vertical position and its potential energy will reach its maximum value. Since the system was at rest, its potential energy at the initial moment is zero. In this case, the potential energy of body 1 will decrease by an amount equal to the work done by gravity when the body moves a distance h. From the law of conservation of energy we obtain the equation: m1gh = ΔE = -m1gh, where m1 is the mass of body 1, g is the acceleration of gravity, h is the height to which body 1 rose.

The solution to the problem is to find the distance by which body 1 will move after lowering the rod to a vertical position. From the equation we can express the height h to which body 1 rose: h = 0. Thus, body 1 will not move in the horizontal direction, and the answer to the problem is 0.1.

The digital product is presented in Microsoft Word 2003 format, it takes into account all the conditions of the problem, and offers detailed steps necessary to achieve the correct answer. Using the formula editor makes it easy to read and check each step of the solution. By purchasing this product, you will have access to a complete solution that you can use to prepare for exams, test knowledge, and expand your mechanical knowledge.

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Product description:

Solution to problem 14.1.18 from the collection of Kepe O.?. is a detailed description of the process of solving a physical problem involving the movement of bodies on a horizontal guide and a vertically lowered rod.

In the problem, it is necessary to determine the distance over which a body weighing 4 kg will move when lowering a homogeneous rod weighing 2 kg and length l = 0.6 m. The system is initially at rest, and the rod is lowered under the influence of gravity to a vertical position.

The solution to the problem is designed in Microsoft Word 2003 and uses the formula editor. The solution consistently provides all the necessary formulas, calculations and explanations necessary to obtain the correct answer, which is 0.1 meters.

Thus, the solution to problem 14.1.18 from the collection of Kepe O.?. is a useful material for students and schoolchildren studying physics and preparing to take exams and tests.

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