Solution to problem 16.3.10 from the collection of Kepe O.E.

16.3.10. The bicycle moves forward and the front wheel rotates at an angular velocity of ω1 = 20 rad/s. At some point in time, the front fork deviates to the left with a rotation speed of ω2 = 2 rad/s. It is necessary to calculate the gyrostatic moment if the moment of inertia of the front wheel I1 = 0.16 kg • m2. The answer is 6.4.

The gyrostatic moment can be calculated using the formula:

L = I1 * ω2

where I1 is the moment of inertia of the front wheel, and ω2 is the angular speed of rotation of the fork.

Substituting the values, we get:

L = 0.16 * 2 = 0.32 kg • m2/s

Answer: L = 6.4.

Solution to problem 16.3.10 from the collection of Kepe O.?.

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Solution to problem 16.3.10 from the collection of Kepe O.?. consists in determining the gyrostatic (gyro-effect) moment of the bicycle at the moment of deflection of the front fork.

To do this, you need to know the angular speed of the front wheel of the bicycle ω1 = 20 rad/s, the angular speed of deflection of the front fork ω2 = 2 rad/s, and the moment of inertia of the front wheel I1 = 0.16 kg • m2.

The gyrostatic moment can be found using the formula:

M = I1 * ω1 * ω2

Substituting the known values, we get:

M = 0.16 kg • m2 * 20 rad/s * 2 rad/s = 6.4 N • m

Thus, the gyrostatic moment of the bicycle at the moment of deflection of the front fork is 6.4 N • m.

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