Solution to problem 13.7.2 from the collection of Kepe O.E.

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Consider a ball M with a mass m = 0.2 kg, which moves at a speed v = 19.62 m/s relative to a vertical tube attached to a vertical shaft 1 at a distance l = 0.5 m. The shaft rotates at a constant angular velocity с = 5 rad/s. It is necessary to calculate the transfer force of inertia of the ball. Answer: 2.5.

The transfer force of inertia is a force that acts on a body during its movement in a curved trajectory. In this case, the ball moves in a circle with radius l, so it experiences a transfer force of inertia. To calculate this force, you must use the formula Fi = mrω^2, where Fi is the transfer force of inertia, m is the mass of the body, r is the radius of the circle along which the body moves, and ω is the angular speed of rotation of the shaft.

Substituting known values, we get: Fi = 0.20,5(5^2) = 2.5 N.

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I present to you a digital product that solves problem 13.7.2 from the collection of Kepe O.?.

This problem consists of calculating the transfer force of inertia of a ball M with mass m = 0.2 kg, which moves at a speed v = 19.62 m/s relative to a vertical tube attached to vertical shaft 1 at a distance l = 0.5 m. The shaft rotates with a constant angular velocity с = 5 rad/s.

The transfer force of inertia is a force that acts on a body during its movement in a curved trajectory. To calculate this force, we use the formula Fi = mrω^2, where Fi is the transfer force of inertia, m is the mass of the body, r is the radius of the circle along which the body moves, and ω is the angular speed of rotation of the shaft.

Substituting the known values, we get Fi = 0.20.5(5^2) = 2.5 N.

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This product is an excellent choice for students and teachers studying physics. Thanks to the convenient format and meaningful answer to the problem, you can significantly improve your performance in this science.

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Solution to problem 13.7.2 from the collection of Kepe O.?. associated with determining the transfer force of inertia of the ball. Given a ball M with a mass m = 0.2 kg, which moves at a speed v = 19.62 m/s relative to a vertical tube attached to a vertical shaft 1 at a distance l = 0.5 m. The shaft rotates at a constant angular velocity с = 5 rad/s.

To solve the problem, it is necessary to determine the transfer force of inertia of the ball, which arises when the tube moves together with the shaft. This force is caused by a change in the direction of movement of the ball when the tube rotates around a vertical axis.

The transfer force of inertia is determined by the formula: F = m*(l*ω)^2, where m is the mass of the ball, l is the distance from the ball to the axis of rotation, ω is the angular velocity of rotation of the tube.

Substituting the known values, we get:

F = 0.2*(0.5*5)^2 = 2.5 N

Thus, the transfer force of inertia of the ball when the tube moves together with the shaft is equal to 2.5 N.

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