Expanding, a triatomic gas does work equal to

During isobaric expansion, a triatomic gas performs work equal to 245 J. It is necessary to determine how much heat was transferred to the gas during the expansion process.

Let us consider the process of isobaric expansion of a gas. In this case, the gas pressure remains constant and the volume increases. Thus, the work done by the gas is equal to the constant pressure multiplied by the change in volume:

A = РΔV

where A is the work done by the gas; P - constant gas pressure; ΔV - change in volume.

In our case, the work of the gas is known and equal to 245 J. Therefore, we can express the change in volume:

ΔV = A/Р

To determine the amount of heat transferred to the gas, we use the first law of thermodynamics:

Q = ΔU + A

where Q is the amount of heat transferred to the gas; ΔU is the change in the internal energy of the gas; A is the work done by the gas.

If the expansion process occurs without changing the internal energy of the gas (that is, without heat exchange with the environment), then ΔU = 0 and the formula simplifies:

Q = A

So, the amount of heat transferred to the gas during isobaric expansion is 245 J.

Product description

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The digital book “When expanding, a triatomic gas does work equal to” is a unique popular science material that contains a detailed description of the process of isobaric expansion of a triatomic gas and the calculation of the amount of heat transferred to the gas during the expansion process. In addition, the book contains many interesting facts and examples that will help you better understand the physical phenomena occurring in the world around us.

In this case, if a triatomic gas expanded isobarically and performed work equal to 245 J, then the amount of heat transferred to the gas can be determined using the first law of thermodynamics, which states: Q = ΔU + A, where Q is the amount of heat, ΔU is the change internal energy of the gas, A - work done by the gas. If the expansion process occurs without changing the internal energy of the gas, then ΔU = 0 and the formula simplifies: Q = A. So, the amount of heat transferred to the gas during isobaric expansion is equal to 245 J.

We present to you the digital book “When expanding, a triatomic gas does work equal to.” This book contains unique popular science material on thermodynamics and physics of gases, in which you will find a detailed description of the process of isobaric expansion of a triatomic gas and calculation of the amount of heat transferred to the gas during the expansion process.

To solve this problem, the first law of thermodynamics is used, which states that the change in the internal energy of a gas is equal to the sum of the amount of heat transferred to the gas and the work done by the gas. In this case, the expansion process occurs isobarically, that is, at constant pressure, so the work of the gas is equal to the product of constant pressure and the change in volume.

From the conditions of the problem, the work done by the gas is known, which is equal to 245 J. Thus, we can express the change in volume: ΔV = A/P, where A is the work of the gas, P is the constant pressure of the gas.

To determine the amount of heat transferred to the gas, we use the first law of thermodynamics: Q = ΔU + A, where Q is the amount of heat transferred to the gas; ΔU is the change in the internal energy of the gas; A is the work done by the gas.

If the expansion process occurs without changing the internal energy of the gas (that is, without heat exchange with the environment), then ΔU = 0 and the formula simplifies: Q = A.

Thus, the amount of heat transferred to the gas is 245 J.

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The product is not listed in the description. Instead, a problem from the field of physics is given.

Condition of the problem: when expanding, a triatomic gas does work equal to 245 J. It is necessary to find the amount of heat that was transferred to the gas, provided that it expanded isobarically.

To solve this problem, it is necessary to use the Gay-Lussac law, which states that in an isobaric process, the ratio of the change in volume to the initial volume of the gas is equal to the ratio of the change in temperature to the initial temperature of the gas:

(V2-V1)/V1 = (T2-T1)/T1,

where V1 and T1 are the initial volume and temperature of the gas, V2 and T2 are the final volume and temperature of the gas.

It is also necessary to use the formula for the work done by a gas in an isobaric process:

A = p * (V2 - V1),

where p is the gas pressure.

Since the gas expands isobarically, the pressure of the gas does not change, therefore, the work done by the gas is:

A = p * (V2 - V1) = p * V * (T2 - T1) / T1,

where V = V1 is the initial volume of gas.

The heat transferred to the gas is determined by the first law of thermodynamics:

Q = ΔU + A,

where ΔU is the change in the internal energy of the gas.

Since the process is isobaric, the change in the internal energy of the gas is associated with a change in its temperature:

ΔU = C * m * (T2 - T1),

where C is the specific heat capacity of the gas at constant pressure, m is the mass of the gas.

Therefore, the amount of heat transferred to the gas is equal to:

Q = C * m * (T2 - T1) + p * V * (T2 - T1) / T1.

To solve the problem, it is necessary to know the values ​​of the mass of the gas, the specific heat capacity at constant pressure and the initial temperature of the gas, which are not indicated in the condition.

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