Here are examples of solving some of these problems:
Consider the series $\sum_{n=1}^\infty \frac{1}{n^2}$. To prove convergence, we use the comparison test: $\frac{1}{n^2}
Consider the series $\sum_{n=1}^\infty \frac{1}{n}$, $\sum_{n=1}^\infty \frac{1}{n\ln n}$ and $\sum_ {n=2}^\infty \frac{1}{n\ln^2 n}$. To examine them for convergence, we will use the comparison criterion: a) $\frac{1}{n}\frac{1}{n}$, therefore, $\sum_{n=2}^\infty \frac{1}{n \ln^2 n}$ diverges.
Consider the alternating series $\sum_{n=1}^\infty \frac{(-1)^{n+1}}{n}$. To study convergence, we apply Leibniz’s test: the sequence $\frac{1}{n}$ monotonically decreases and tends to zero, therefore, the series converges. To check absolute convergence, we apply the comparison test: $\left|\frac{(-1)^{n+1}}{n}\right|\leq\frac{1}{n}$, therefore, the series is also absolutely convergent .
Consider the alternating series $\sum_{n=1}^\infty \frac{(-1)^{n+1}}{n^p}$, where $p>0$. To study convergence, we apply Leibniz’s test: the sequence $\frac{1}{n^p}$ monotonically decreases and tends to zero, therefore, the series converges. To check absolute convergence, we apply the comparison test: $\left|\frac{(-1)^{n+1}}{n^p}\right|\leq\frac{1}{n^p}$, therefore, the series converges absolutely for $p>1$ and diverges for $p\leq1$.
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