Nitrogen weighing 200 g is heated at constant pressure from temperature t1=20°C to temperature t2=200°C. It is necessary to determine the amount of heat absorbed by the gas, the increase in its internal energy and the work done by the gas.
Answer:
To solve the problem, we will use the equation of state of an ideal gas:
pV = nRT,
where p is the gas pressure, V is its volume, n is the amount of gas substance, R is the universal gas constant, T is the absolute temperature of the gas.
From the conditions of the problem, the mass of the gas m = 200 g and its composition are known, so we can determine the amount of gas substance n using the formula:
n = m/M,
where M is the molar mass of the gas. For nitrogen M = 28 g/mol.
The amount of gas substance, and therefore its volume, can be determined by the initial conditions:
p1V1 = nRT1,
where p1 and T1 are the pressure and temperature of the gas before heating, V1 is its volume.
Similarly, according to the final conditions, the final volume of gas can be determined:
p2V2 = nRT2.
At constant pressure, the work done by a gas is calculated by the formula:
A = p(V2 - V1).
The amount of heat absorbed by the gas when heated is determined by the formula:
Q = nСp(T2 - T1),
where Cp is the heat capacity of gas at constant pressure.
For nitrogen, Cp = 29 J/(mol K).
Thus, the amount of heat absorbed by the gas when heated is equal to:
Q = (0.00714 mol) × (29 J/(mol K)) × (200°C - 20°C) = 39.9 kJ.
The increase in internal energy of a gas can be determined by the formula:
ΔU = Q - A = 39.9 kJ - 15.68 kJ = 24.22 kJ.
Answer:
The amount of heat absorbed by the gas during heating is 39.9 kJ. The increase in internal energy of the gas is 24.22 kJ. The work done by the gas is 15.68 kJ.
This digital product contains a detailed description of a physics problem involving heating 200 g of nitrogen at constant pressure. The description presents a solution to the problem, including formulas and laws of physics used for calculations. In addition, you will find the derivation of the calculation formula and the answer to the problem.
The problem can be useful for students and teachers of physics, as well as for anyone interested in physics. By ordering this digital product, you will have access to high-quality and understandable material that will help you better understand the mechanisms of physical processes.
Product description:
The digital product "Problem 20322. Detailed solution" is a detailed description of the solution to a physics problem involving heating 200 g of nitrogen at constant pressure. The description presents the formulas and laws of physics used for calculations, as well as the derivation of the calculation formula and the answer to the problem.
The problem can be useful for students and teachers of physics, as well as for anyone interested in physics. By ordering this digital product, you will have access to high-quality and understandable material that will help you better understand the mechanisms of physical processes.
The problem requires finding the amount of heat that is absorbed by nitrogen when heated from a temperature t°1 = 20°C to a temperature t°2 = 200°C at constant pressure, as well as the increase in internal energy of the gas and the work done by the gas. To solve the problem, the equation of state of an ideal gas, formulas for determining the amount of gas substance, its volume, heat capacity and work are used.
Once you receive this digital product, you will be able to quickly and easily solve this physics problem and also better understand the operation of an ideal gas when heated at constant pressure.
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This product is not a physical item, but rather a problem in the field of physics. The product description you provided describes the process of heating 200 g of nitrogen at constant pressure from a temperature of 20°C to a temperature of 200°C.
To solve this problem, it is necessary to use the laws of thermodynamics, namely the first law of thermodynamics, which establishes a connection between the change in the internal energy of a gas, the amount of heat received or given off by the gas, and the work done by the gas.
When heating nitrogen at constant pressure, the work done by the gas will be equal to the product of the pressure and the change in volume of the gas. If the volume of the gas does not change, then the work done by the gas will be zero.
The amount of heat absorbed by the gas can be calculated using the formula Q = mcΔT, where m is the mass of the gas, c is the specific heat of the gas at constant pressure, ΔT is the change in temperature.
The increase in internal energy of a gas can be calculated using the formula ΔU = Q - A, where Q is the amount of heat absorbed by the gas, A is the work done by the gas.
Thus, to solve this problem it is necessary to know the specific heat capacity of nitrogen at constant pressure and the pressure at which heating occurs. The answer to the problem can be obtained by substituting known values into the appropriate formulas.
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Solution to problem 7.4.4 from the collection of Kepe O.E. - 7.4.4 Необходимо определить ускорение точки Н в момент... ...