A point light source with λ = 500 nm is placed on the

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Product Name: Point Light Source

Description:

• This digital product is intended for use as an educational aid in physics.
• It has a point light source with a wavelength of λ = 500 nm, which makes it possible to study the properties of light in a narrow spectral range.
• Can be used to conduct experiments to study the phenomenon of interference and diffraction of light at small holes.
• The product contains detailed instructions for use and experimentation.
• Suitable for schoolchildren and students, as well as for lovers of physics and scientific experiments.

Price: 499 rub.

Product Name: Point Light Source

This digital product is intended for use as an educational aid in physics. It has a point light source with a wavelength of λ = 500 nm, which makes it possible to study the properties of light in a narrow spectral range. Can be used to conduct experiments to study the phenomenon of interference and diffraction of light at small holes. The product contains detailed instructions for use and experimentation. Suitable for schoolchildren and students, as well as for lovers of physics and scientific experiments.

Price: 499 rub.

This digital product is a point source of light with a wavelength of λ = 500 nm, which can be used as an educational tool in physics. It allows you to study the properties of light in a narrow spectral range and conduct experiments to study the phenomenon of interference and diffraction of light by small holes.

To carry out the experiment described in problem 40012, it is necessary to place a point light source at a distance a = 0.5 m in front of an opaque obstacle with a hole of radius r = 0.5 mm and determine the distance b from the obstacle to the point for which the number m of open Fresnel zones will be equal to: a) 1; b) 5; at 10 o'clock.

To solve the problem, you can use the formula to determine the distance b from the obstacle to the point at which the number of open Fresnel zones is equal to m:

b = mλa/2r

where λ is the wavelength of light, a is the distance from the light source to the obstacle, r is the radius of the hole in the obstacle, m is the number of open Fresnel zones.

The detailed instructions included with the product provide a brief record of the conditions of the problem, formulas and laws used in the solution, the derivation of the calculation formula and the answer. If you have any questions about the solution, you can ask for help.

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This product is a point light source with a wavelength of 500 nm, which is installed at a distance of 0.5 m in front of an opaque barrier with a hole with a radius of 0.5 mm. The task is to determine the distance b from the obstacle to the point for which the number of open Fresnel zones will be equal to 1, 5 or 10.

To solve the problem it is necessary to use the Fresnel formulas:

m = (a * sqrt(n))/λ

where m is the number of open Fresnel zones, a is the distance from the light source to the obstacle, n is the distance from the obstacle to the point, λ is the wavelength of light.

You can also use the formula to find the distance b:

b = a * n / (n - sqrt(r^2 + n^2))

where r is the radius of the hole in the obstacle.

When solving the problem, it is necessary to sequentially substitute the values ​​of a, λ, r and the required value of the number m, and find the corresponding distance n. After this, using the second formula we find the required distance b.

For example, with the required value of the number of opening Fresnel zones equal to 1, the initial data will be as follows:

a = 0.5 m λ = 500 nm = 0.0005 m r = 0.5 mm = 0.0005 m m = 1

Substituting the values ​​into the Fresnel formula, we get:

1 = (0.5 * sqrt(n))/0.0005

Where can we find it from:

n = ((0.0005 * 1)^2)/0.5 = 0.00025 m

Substituting the obtained values ​​into the formula for calculating b, we get:

b = 0.5 * 0.00025 / (0.00025 - sqrt(0.0005^2 + 0.00025^2)) ≈ 0.00057 m

Thus, under the conditions of the problem, the distance b from the obstacle to the point for which the number of open Fresnel zones is equal to 1 is approximately 0.00057 m.

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1. Excellent product! Perfectly illuminates the work area.
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6. This product helps me work in the dark, creating comfortable conditions.
7. Excellent combination of price and quality. I recommend to buy!

Peculiarities:

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