Solution to problem 15.1.6 from the collection of Kepe O.E.

Solution to problem 15.1.6 from the collection of Kepe O..

We present to your attention the solution to problem 15.1.6 from the collection of O.. Kepe problems, which is available in digital format.

This digital product is intended for those studying physics and mathematics, as well as for anyone interested in solving problems. Solving Problem 15.1.6 will help you more deeply understand how gravity works when an object moves in a vertical plane.

In our digital product you will find a detailed description of the solution to the problem, which is accompanied by formulas, graphs and explanations. Beautiful design in HTML format will allow you to comfortably study the material on any device.

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Digital product "Solution to problem 15.1.6 from the collection of Kepe O.?." is a detailed description of the solution to physical problem No. 15.1.6 from the collection O.?. Kepe in digital format. Solving this problem will help you better understand how gravity works when an object moves in a vertical plane.

In the product you will find formulas, graphs and explanations that describe in detail the solution to the problem. The design is made in HTML format, which makes it convenient to study the material on any device.

In addition, this product can be useful both for students studying physics and mathematics, and for anyone interested in solving problems.

The cost of the product is only 99 rubles. By purchasing this product, you can easily and quickly master the solution to problem 15.1.6 from the collection O.?. Kepe.

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Problem 15.1.6 from the collection of Kepe O.?. describes a situation in which a mass of 0.4 kg is suspended from a thread 1 meter long. It is required to find the work done by the force of gravity of the load when moving it from position 2 to position 1 in the vertical plane.

To solve this problem, you need to know that the work of a force is defined as the product of the modulus of the force and the path traveled by the body in the direction of the force. In this case, the force of gravity is directed vertically downward, so the path traveled by the load is equal to the difference in height between positions 2 and 1, that is, 1 meter. The modulus of gravity is equal to the product of the mass of the load and the acceleration of gravity, which on Earth is taken to be equal to 9.81 m/s^2. So, the work of gravity is calculated using the following formula:

work = force * path = m * g * h

where m is the mass of the load, g is the acceleration of gravity, h is the height to which the load rises.

Substituting the known values, we get:

work = 0.4 * 9.81 * 1 = 3.924 J (answer rounded to 3.92 J)

Thus, the force of gravity does 3.92 J of work when moving the load from position 2 to position 1 in the vertical plane.

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