Straight wire length l=40 cm through which current flows

Let's say we have a wire 40 cm long, through which a current of 100 A flows. This wire moves in a uniform magnetic field with an induction of 0.5 Tesla. If we move the wire a distance of 40 cm in the direction perpendicular to the induction lines and the wire, what work A will be done by the forces acting on the wire from the field?

To solve this problem, we can use the formula to calculate the work done by a vector field on a charge:

A = F * s * cos(alpha)

where A is work, F is the force acting on the charge, s is the movement of the charge, alpha is the angle between the direction of the force and the direction of movement.

In this problem, we have a wire through which current flows, and a magnetic field acting on this wire. The force acting on the wire can be calculated using the Lorentz formula:

F = q * v * B

where F is force, q is charge, v is charge speed, B is magnetic field induction.

The charge of a wire can be expressed in terms of current and time:

q = I * t

where I is current, t is time.

The charging speed can be expressed in terms of wire length and travel time:

v = l / t

where l is the length of the wire, t is the time.

Thus, the force acting on the wire will be equal to:

F = I * l * B

Since the wire moves perpendicular to the induction lines and the wire, the angle between the direction of the force and the direction of movement is 90 degrees, and cos(90) = 0. Therefore, the work done by the forces acting on the wire will be zero:

A = F * s * cos(alpha) = 0

Thus, when moving the wire a distance of 40 cm in the direction perpendicular to the induction lines and the wire, the forces acting on the wire from the field will not do any work.

Straight wire

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A straight wire with a length of l=40 cm, through which a current of force I=100 A flows, moves in a uniform magnetic field with induction B=0.5 Tesla. Let us find the work A performed by the forces acting on the wire from the field when moving it a distance s = 40 cm, if the direction of movement is perpendicular to the induction lines and the wire.

To solve this problem, we use the formula for calculating the Lorentz force acting on a wire in a magnetic field:

F = I * l * B

where F is the force acting on the wire, I is the current strength, l is the length of the wire, B is the magnetic field induction.

Since the movement of the wire occurs perpendicular to the induction lines and the wire, the angle between the direction of the force and the direction of movement is 90 degrees, and cos(90) = 0. Therefore, the work done by the forces acting on the wire will be zero:

A = F * s * cos(alpha) = 0

Answer: the work done by the forces acting on the wire from the field, when moving it a distance s = 40 cm, if the direction of movement is perpendicular to the induction lines and the wire, is zero.

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A straight wire 40 cm long carrying a current of 100 A. The wire moves in a uniform magnetic field with an induction of 0.5 Tesla.

For this problem, you need to find the work A performed by the forces acting on the wire from the magnetic field when moving it a distance of 40 cm, perpendicular to the induction lines and the wire.

To solve the problem, you can use the formula to calculate the work done by the force acting on a wire in a magnetic field:

А = F * s * sin(φ),

where F is the force acting on the wire, s is the movement of the wire, φ is the angle between the direction of the force and the direction of movement.

In this case, the force acting on the wire is equal to:

F = B * I * l,

where B is the magnetic field induction, I is the current flowing through the wire, l is the length of the wire in the magnetic field.

Thus, the work done by the force acting on the wire when moving it a distance of 40 cm will be equal to:

A = B * I * l * s * sin(φ) = 0.5 T * 100 A * 0.4 m * 0.4 m * 1 = 8 J.

Answer: the work of forces acting on the wire when moving it a distance of 40 cm, perpendicular to the induction lines and the wire, is equal to 8 J.

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