The surface of the zinc photocathode is illuminated

When a zinc photocathode is illuminated with monochromatic light with a wavelength of 0.28 µm, a photoelectron flies out towards the incident quantum. The electron work function for zinc is 3.74 eV. It is necessary to determine the total impulse transferred to the photocathode.

To solve the problem, we use the Einstein formula:

E = hf - φ,

where E is the photon energy, h is Planck's constant, f is the frequency of light, φ is the electron work function.

Let's rewrite the formula in a form more convenient for us:

p = E/c = hf/c - φ/c,

where p is the photon momentum, c is the speed of light.

To find the total momentum transferred to the photocathode, it is necessary to multiply the photon momentum by the number of emitted electrons. Since only the wavelength of light is known from the problem conditions, it is necessary to find the frequency of light:

f = c/λ = 310^8 m/s / 0.2810^-6 m = 1.07*10^15 Hz.

Now we can find the photon momentum:

p = hf/c - φ/c = (6,6310^-34 Jwith * 1.0710^15 Hz) / 310^8 m/s - 3.74 eV / (1.610^-19 J/eV * 310^8 m/s) = 1.1110^-26 kgm/s.

Since the photoelectron flies out towards the incident quantum, the total momentum transferred to the photocathode will be equal to the photon momentum. Therefore, the total impulse is 1.1110^-26 kgm/s.

Answer: the total impulse transferred to the photocathode is 1.1110^-26 kgm/s.

Product Description: Digital Product

Product Name: Physics Learning Digital Product "The surface of the zinc photocathode is illuminated"

The digital product "The surface of a zinc photocathode is illuminated" is an educational material for studying the phenomenon of the photoelectric effect in physics.

The product provides a detailed description of the phenomenon of the photoelectric effect and its laws, as well as a solution to the problem of determining the total impulse transferred to the photocathode when illuminated with monochromatic light with a wavelength of 0.28 microns.

All materials are presented in an easy-to-read format, with detailed explanations and diagrams. The product can be useful for both school and university students, teachers and researchers.

The digital product "The surface of a zinc photocathode is illuminated" is an excellent choice for those who want to deepen their knowledge of physics and get acquainted with the phenomenon of the photoelectric effect.

This digital product "The surface of a zinc photocathode is illuminated" is an educational material for studying the phenomenon of the photoelectric effect in physics. The product contains a detailed description of the phenomenon of the photoelectric effect and its laws, as well as a solution to the problem of determining the total momentum transferred to the photocathode when illuminated with monochromatic light with a wavelength of 0.28 microns, provided that the photoelectron flies out towards the incident quantum, and the work function of the electron for zinc is 3, 74 eV.

The product presents materials in an easy-to-read format, with detailed explanations and diagrams. The product can be useful both for school and university students, as well as for teachers and researchers who want to deepen their knowledge of physics and get acquainted with the phenomenon of the photoelectric effect.

Solving the problem involves using the Einstein formula to determine the photon momentum, as well as applying the laws of the photoelectric effect. The answer to the problem is 1.1110^-26 kgm/s. If you have any questions about the solution, you can ask for help.

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Product description:

A zinc photocathode, illuminated by monochromatic light with a wavelength of 0.28 μm, imparts a total impulse when a photoelectron is emitted towards the incident quantum. The electron work function for zinc is 3.74 eV.

To solve the problem, it is necessary to use the Einstein formula for the photoelectric effect:

E = h*f - φ,

where E is the kinetic energy of the emitted electron, h is Planck's constant, f is the frequency of the incident light, φ is the work function.

For monochromatic light with wavelength λ and speed of light c, the relation can be used:

f = c/min.

Thus, for a given wavelength, one can calculate the frequency of the incident light and then find the kinetic energy of the emitted electron. The total momentum imparted to the photocathode will be equal to the momentum of the emitted electron.

Substituting the values ​​into the Einstein formula, we get:

E = h*c/λ - f

E = 6,626 * 10^-34 * 3 * 10^8 / (0,28 * 10^-6) - 3,74 * 1,6 * 10^-19

E = 1.99 * 10^-19 J

To calculate the momentum, you need to know the speed of the emitted electron. In the absence of other data, you can use the formula to relate energy and momentum in the free movement of an electron:

E = p^2 / (2m)

where p is the momentum of the electron, m is its mass.

Solving the equation for p, we get:

p = sqrt(2mE)

For an electron, mass m is equal to 9.11 * 10^-31 kg. Substituting the values, we get:

p = sqrt(2 * 9,11 * 10^-31 * 1,99 * 10^-19)

p = 6.60 * 10^-23 kg*m/s

Thus, the total impulse imparted to the photocathode is 6.60 * 10^-23 kg*m/s.

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