Solution to problem 3.2.26 from the collection of Kepe O.E.

3.2.26 Rod AV

The length of rod AB is 2 meters; it is subject to a uniformly distributed load with intensity q = 100 N/m. It is required to determine the reaction of support A. (Answer: 141)

Answer:

The reaction of support A is equal to the sum of all external forces acting on rod AB. Due to the uniformly distributed load, the force q will act on the middle of the rod, i.e. at a distance of 1 m from support A. Then:

Support reaction A = q * L/2 = 100 * 2/2 = 100 N

Thus, the reaction of support A is 100 N.

Solution to problem 3.2.26 from the collection of Kepe O..

This product - a digital product, is a solution to problem 3.2.26 from the collection "Problems on the strength of materials" by Kepe O.. The problem is to determine the reaction of support A to a rod AB, 2 meters long, which is loaded with a uniformly distributed load of intensity q = 100 N/m.

By purchasing this digital product, you will receive a solution to Problem 3.2.26 in a convenient format, ready for use in your studies or professional activities. Beautiful design of the html page will make using the product as comfortable and enjoyable as possible.

Don't miss the opportunity to purchase a useful and high-quality digital product - the solution to problem 3.2.26 from the collection of Kepe O..!

This product is a digital solution to problem 3.2.26 from the collection “Problems on Strength of Materials” by Kepe O.. The problem requires determining the reaction of support A to a rod AB 2 m long, which is loaded with a uniformly distributed load with intensity q = 100 N/m .

The solution to the problem is based on the principle of equilibrium, according to which the reaction of support A is equal to the sum of all external forces acting on rod AB. Due to the uniformly distributed load, the force q will act on the middle of the rod, i.e. at a distance of 1 m from support A. Therefore, the reaction of support A will be equal to q * L/2 = 100 * 2/2 = 100 N.

By purchasing this digital product, you will receive a ready-made solution to the problem in a convenient format, ready for use in your studies or professional activities. Beautiful design of the html page will make using the product as comfortable and enjoyable as possible. Don't miss the opportunity to purchase a useful and high-quality digital product - the solution to problem 3.2.26 from the collection of Kepe O..! The answer to the problem is 141.

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Problem 3.2.26 from the collection of Kepe O.?. consists in determining the reaction of support A to rod AB, 2 meters long, which is loaded with a uniformly distributed load with intensity q = 100 N/m.

To solve the problem, it is necessary to use equilibrium equations to determine the reaction of the support A. Since the rod is in equilibrium, the sum of all forces acting on it must be equal to zero.

Consequently, the reaction of the support A will be equal to the force acting on the rod from the side of the load, i.e. the product of the load intensity and the length of the rod:

A = q * L = 100 N/m * 2 m = 200 N

Answer: 200 N.

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