Solution K2-56 (Figure K2.5 condition 6 S.M. Targ 1989)

In problem K2-56 (Figure K2.5 condition 6 S.M. Targ 1989), the mechanism consists of three stepped wheels 1-3, which are meshed with each other or connected by a belt drive, a gear rack 4 and a load 5 tied to the end of the thread wound around one of the wheels (see Fig. K2.0 - K2.9 and table K2). The radii of the wheel steps are respectively equal: for wheel 1 - r1 = 2 cm, R1 = 4 cm, for wheel 2 - r2 = 6 cm, R2 = 8 cm, for wheel 3 - r3 = 12 cm, R3 = 16 cm. On rims wheels, points A, B and C are located. In the “Given” column of the table, the law of motion or the law of change in speed of the driving link of the mechanism is indicated, where φ1(t) is the law of rotation of the wheel 1, s2(f) is the law of motion of the rack 4, ω2(t ) is the law of change in the angular velocity of wheel 2, v5(t) is the law of change in the speed of load 5, etc. (everywhere φ is expressed in radians, s in centimeters, t in seconds). The positive direction for φ and ω is counterclockwise, for s4, s5 and v4, v5 - down. It is necessary to determine at the moment of time t1 = 2 s the velocities (v - linear, ω - angular) and accelerations (a - linear, ε - angular) of the corresponding points or bodies indicated in the table in the "Find" columns (v5 - speed of load 5, etc.) .d.).

Solution K2-56 (Figure K2.5 condition 6 S.M. Targ 1989)

Solution K2-56 is a digital product that is a solution to a problem from the textbook by S.M. Targa "Problems in Physics" 1989 edition. This product is a detailed description of a mechanism consisting of three gear wheels, a belt drive, a rack and a weight attached to the end of a string. Solution K2-56 contains a table with data on the law of motion and the law of change in speed of the driving link of the mechanism, as well as the radii of the wheel steps and the location of points on the wheel rims.

This product is recommended for students and teachers studying mechanics and solving physics problems. Solution K2-56 will help to better understand the principles of operation of step mechanisms and the laws of motion of bodies in space.

Solution K2-56 is a product that is designed to solve problem K2-56 from the textbook by S.M. Targa "Problems in Physics" 1989 edition. This product contains a detailed description of the mechanism, which consists of three gear wheels, a belt drive, a rack and a weight attached to the end of the thread. Solution K2-56 includes a table with data on the law of motion and the law of change in speed of the driving link of the mechanism, as well as the radii of the wheel steps and the location of points on the wheel rims.

This product is intended for students and teachers who study mechanics and solve physics problems. Solution K2-56 can help to better understand the principles of operation of step mechanisms and the laws of motion of bodies in space. At the time t1 = 2 s, it is necessary to determine the velocities (v - linear, ω - angular) and accelerations (a - linear, ε - angular) of the corresponding points or bodies indicated in the table in the "Find" columns (v5 - speed of load 5, etc. .d.).

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The K2-56 solution is a mechanism consisting of three stepped wheels and a gear rack connected by a belt drive. The weight is tied to the end of a thread wound around one of the wheels. The radii of the wheel steps are different: for wheel 1 – r1 = 2 cm, R1 = 4 cm, for wheel 2 – r2 = 6 cm, R2 = 8 cm, for wheel 3 – r3 – 12 cm, R3 = 16 cm. On the wheel rims points A, B and C are located.

The table shows the laws of motion or changes in the speed of the leading link of the mechanism depending on time. For a certain moment of time t1 = 2 s, the velocities and accelerations of the corresponding points or bodies are indicated. For example, v5 - load speed 5.

It is necessary to determine the corresponding values ​​of velocities and accelerations at the time t1 = 2 s, indicated in the table in the “Find” columns. Velocities can be linear (v) or angular (ω), and accelerations can be linear (a) or angular (ε). The positive direction for angular quantities (φ and ω) is counterclockwise, for linear quantities (s and v) - down.

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