A positively charged particle whose charge is equal to

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A positively charged particle with a charge equal to the elementary charge has undergone an acceleration of 60,000 V and is directed towards the nucleus of a lithium atom, which has a charge equal to three elementary charges. It is necessary to determine the smallest distance between the particle and the nucleus that can be achieved. The initial distance between the particle and the nucleus can be considered almost infinitely large.

To solve the problem, you can use Coulomb's law, which states that the force of interaction between two point charges is proportional to their magnitudes and inversely proportional to the square of the distance between them. It also follows from the law of conservation of energy that the kinetic energy of a particle must be equal to its potential energy at the moment of closest approach to the nucleus.

Using these laws and taking the initial distance between the particle and the nucleus to be equal to infinity, we can solve the problem and determine that the shortest distance between the particle and the lithium nucleus is approximately 2.3 * 10^-14 meters.

Product description

We present to your attention a digital product - “Positively charged particle”.

This unique product describes a particle whose charge is equal to the elementary charge. It has passed through an accelerating potential difference of 60,000 V and is directed to the nucleus of a lithium atom, the charge of which is equal to three elementary charges.

This fascinating description will help you understand the basics of physics and the principles of interaction of charges in an atom.

Buy Positively Charged Particle now and expand your physics horizons!

The product description is a description of the conditions of a physics problem in which a positively charged particle with a charge equal to the elementary charge is considered, undergoing an acceleration of 60,000 V and heading towards the nucleus of a lithium atom, which has a charge equal to three elementary charges. To solve this problem, Coulomb's law is used, which determines the strength of interaction between charges, and the law of conservation of energy, which allows us to determine the smallest distance between the particle and the nucleus that can be achieved. The solution to the problem shows that the shortest distance between a particle and a lithium nucleus is approximately 2.3 * 10^-14 meters.

The product description also states that this is a unique digital product that will help you understand the basics of physics and the principles of interaction of charges in an atom. Buyers can purchase this product to expand their horizons in the field of physics and deepen their knowledge in this science.

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The description of the product is not entirely clear, since the charge of an elementary particle equal to the elementary charge is not a product. However, based on the provided problem, conclusions can be drawn about the motion of a positively charged particle.

From the conditions of the problem it is known that the particle has a charge equal to the elementary charge and flies towards the nucleus of a lithium atom, the charge of which is equal to three elementary charges. Also given is the value of the accelerating potential difference equal to 60000 V.

To find the shortest distance a particle can approach the nucleus, we can use the law of conservation of energy and Coulomb's law.

The first step is to find the kinetic energy of the particle using the accelerating potential difference and the charge of the particle. Then, having found the kinetic energy, you can find the minimum distance between the particle and the nucleus at which the kinetic energy of the particle is completely converted into the potential energy of interaction between the particle and the nucleus.

Thus, the calculated solution to the problem can be presented as follows:

Given: particle charge q = e, accelerating potential difference V = 60000 V, charge of the lithium atom nucleus Q = 3e. Find: the smallest distance between the particle and the nucleus r.

Formulas and laws: Coulomb's law for the interaction between charges: F = k * q1 * q2 / r^2; Law of conservation of energy: Eк = ΔEп = q * V; Potential energy of interaction between the particle and the nucleus: Ep = k * q * Q / r.

Answer:

Let's find the kinetic energy of the particle: Ek = q * V = e * 60000 = 60000 eV.
Let's find the minimum distance between the particle and the nucleus: Ek = Ep; q * V = k * q * Q / r; r = k * Q * V / (q * Ek); r = 9 * 10^9 * 3 * e * 60000 / (e * 60000) = 9 * 10^-11 m.

Answer: the shortest distance between a particle and the nucleus is 9 * 10^-11 m.

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