What is the difference in wavelengths of orange rays (lambda = 0.6 µm

This product is a physical quantity - the difference in wavelengths of orange rays. Orange color corresponds to a wavelength of approximately 0.6 micrometers. The difference in wavelength of the orange rays can be determined by subtracting the wavelength of one orange ray from the wavelength of the other orange ray. For example, if one orange beam has a wavelength of 0.6 micrometers and another orange beam has a wavelength of 0.62 micrometers, then the wavelength difference will be 0.02 micrometers. The difference in wavelengths of orange rays can be used in various fields of science and technology, for example, in optics or in measuring physical quantities.

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) and violet rays (lambda = 0.4 µm) can be obtained when light propagates in a vacuum?

This product is not a specific product, but rather a physical question about the difference in wavelengths of orange and violet rays when light propagates in a vacuum.

So, the difference in wavelengths of orange rays (lambda = 0.6 µm) and violet rays (lambda = 0.4 µm) can be calculated using the formula:

Δλ = λ_orange - λ_purple

Δλ = 0.6 μm - 0.4 μm = 0.2 μm

Thus, the difference in wavelengths of orange and violet rays when light propagates in a vacuum is 0.2 microns.

A diffraction grating allows you to resolve spectral lines, the difference in wavelength between which is equal to the difference in the paths of the rays passing through different slits of the grating. For orange rays with a wavelength λ = 0.6 μm and a grating period d = 9 μm, the path difference between adjacent slits will be equal to d sinθ, where θ is the angle between the direction to the slit and the normal to the grating.

For a third-order spectrum, the maxima will be at an angle θ satisfying the condition d sinθ = 3λ. The wavelength difference between the two orange lines resolved by the diffraction grating will be Δλ = λ/3.

Thus, for a given diffraction grating with a width of 3 cm and a period of 9 μm, two orange lines with a wavelength difference Δλ = λ/3 = 0.2 μm can be resolved in the third-order spectrum.

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