Temperature of the heater of a heat engine operating at

The heater temperature of a heat engine operating according to the Carnot cycle is Tn = 373 K, and the refrigerator temperature is Tx = 273 K. The cycle work is A = 1 kJ. It is necessary to depict this cycle in ST coordinates and determine the difference between the maximum and minimum entropy values ​​S of the working fluid. The Carnot cycle is an ideal thermodynamic cycle that consists of two isothermal and two adiabatic processes. On the ST graph, this cycle is represented by a rectangle, the upper horizontal side of which corresponds to the isotherm at temperature Tn, and the lower horizontal side to the isotherm at temperature Tx. The vertical sides of the rectangle correspond to adiabatic processes. To determine the difference between the maximum and minimum entropy values ​​S of the working fluid, it is necessary to know the entropy equation for each of the processes of the Carnot cycle and calculate its values ​​at the maximum and minimum points. Then you should calculate the difference between these values. Our digital store invites you to purchase a unique product - the course "Thermodynamics in Examples". One of the main sections of the course is the topic “Temperature of the heater of a heat engine operating on the Carnot cycle.” In this section you will find detailed information about the thermodynamic Carnot cycle and its features, and you will also be able to familiarize yourself with examples of solving problems related to the determination of work and entropy in the Carnot cycle. Beautiful html design of the course will allow you to easily and quickly navigate the material and find the necessary information. You can study the course materials at any convenient time and anywhere you have access to the Internet. By purchasing our digital product, you not only receive a unique product, but also the opportunity to expand your knowledge in the field of thermodynamics.

The product described is not a physical object, but is a Thermodynamics in Examples course. This course offers detailed information about the thermodynamic Carnot cycle and its features, as well as examples of solving problems related to determining work and entropy in the Carnot cycle. The course is presented in the form of a beautiful HTML design and allows you to study the materials at any convenient time and in any place where there is access to the Internet.

In the problem that has been described, it is required to depict the Carnot cycle in ST coordinates and determine the difference between the maximum and minimum entropy values ​​S of the working fluid. The heater temperature of the heat engine is Tn = 373 K, and the refrigerator temperature is Tx = 273 K. The cycle work is A = 1 kJ.

The Carnot cycle is an ideal thermodynamic cycle consisting of two isothermal and two adiabatic processes. On the ST graph, this cycle is represented by a rectangle, the upper horizontal side of which corresponds to the isotherm at temperature Tn, and the lower horizontal side to the isotherm at temperature Tx. The vertical sides of the rectangle correspond to adiabatic processes.

To determine the difference between the maximum and minimum entropy values ​​S of the working fluid, it is necessary to know the entropy equation for each of the processes of the Carnot cycle and calculate its values ​​at the maximum and minimum points. Then you should calculate the difference between these values.

Problem 20805 offers a detailed solution with a brief record of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer. If you have any questions about the solution, you can ask for help.


***


This product is a heat engine that operates according to the Carnot cycle. The heater temperature is 373 K and the refrigerator temperature is 273 K. The cycle work is 1 kJ.

A heat engine operates according to a cyclic process, which is a sequence of changes in the states of the working fluid that occur during one cycle. In this case, the Carnot cycle consists of two processes: isothermal expansion and isothermal compression, which occur at a constant temperature of the heater and refrigerator, respectively.

Graphically, the Carnot cycle in ST coordinates is a rectangle bounded by isotherms. The maximum value of the entropy of the working fluid is achieved on the heater isotherm, and the minimum - on the refrigerator isotherm.

S - the difference between the maximum and minimum entropy values ​​S of the working fluid is found by the formula:

S = Q / Tн,

where Q is the heat received by the working fluid from the heater, and Tn is the temperature of the heater.

When solving the problem, the laws of thermodynamics and formulas related to thermal processes are used. The calculation formula for finding S was indicated above, and the answer to the problem can be obtained by substituting known values ​​into this formula.


***


  1. I am very pleased with the purchase of the heat machine - it heats quickly and efficiently!
  2. This product exceeded my expectations - it is easy to use and very convenient.
  3. Works like a clock! No problems with temperature or heating.
  4. An excellent digital product for those who want to heat something quickly and efficiently.
  5. I have used this heat machine several times and can confidently say that it has lived up to my expectations.
  6. The product is easy to use and has high performance.
  7. Thanks to the manufacturer for such a great product - it definitely does its job!



Peculiarities:




Very convenient and easy to use digital product.

A high-quality digital product that accurately performs its function.

Quick and accurate digital product customization saves time and effort.

This digital product is excellent value for money.

The digital product exceeded my expectations in terms of usability.

A functional and reliable digital product that helps you get the job done.

The ease of setup and use of the digital product makes it easy for beginners to master.

This digital product helps to significantly speed up work and increase the efficiency of processes.

The digital product does its job perfectly and does not require additional configuration.

Convenient and compact digital product that you can easily take with you on a trip.

Related Products

Additional Information

Rating: 4.6
(95)