Solution to problem 7.6.5 from the collection of Kepe O.E.

Solution to problems 7.6.5: Suppose: a = 0.5 m/s², t = 4 с, v₀ = 0, s₀ = 0. It is required to determine the curvilinear coordinate of a point at time t. We use the formula to determine the curvilinear coordinate of a point:

s = s₀ + v₀t + (a/2)t²

We substitute known values:

s = 0 + 0*4 + (0,5/2)*4² = 4 m

Answer: 4 m. Thus, the curvilinear coordinate of the point at time t = 4 s is equal to 4 m.

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This product is a solution to problem 7.6.5 from the collection of Kepe O.?. in physics. The task is to determine the curvilinear coordinate of a point at time t = 4 s, if it is known that the point moves with a constant tangential acceleration a = 0.5 m/s², initial speed v0 = 0, initial coordinate s0 = 0.

The presented solution to the problem in electronic form has a convenient and beautiful html format, which makes the material easier to read and understand. Users can purchase this product from a digital store and have access to the solution on their devices anytime, anywhere.

This product can be useful to students and teachers who study physics and want to improve their knowledge and skills in this area, as well as anyone who is interested in physics and wants to gain new knowledge in this science. The answer to the problem is 4 m.

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Solution to problem 7.6.5 from the collection of Kepe O.?. consists in determining the curvilinear coordinate of a point at time t = 4 s.

From the conditions of the problem it is known that the point moves with constant tangential acceleration a? = 0.5 m/s2, initial velocity v0 = 0, initial coordinate so = 0, and it is required to determine the curvilinear coordinate at time t = 4 s.

To solve the problem you need to use the kinematics formula:

s = so + v0*t + (a/2)*t^2,

where s is the curvilinear coordinate of the point at time t, so is the initial curvilinear coordinate, v0 is the initial velocity, a is the constant tangential acceleration, t is time.

Substituting the known values, we get:

s = 0 + 0*4 + (0,5/2)*4^2 = 0 + 0 + 4 = 4.

Thus, the curvilinear coordinate of the point at time t = 4 s is equal to 4 meters.

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