Solution to problem 13.7.3 from the collection of Kepe O.E.

In the problem, two bodies are given: load 1 with mass m1 = 1 kg and body 2 moving with acceleration a2 = 2 m/s2 down along a vertical guide. Load 1 descends down an inclined plane, which makes a certain angle with the horizon.

It is necessary to find the pressure force of load 1 on body 2. To solve the problem, you can use Newton’s second law of motion: the force acting on a body is equal to the product of the body’s mass and its acceleration.

Let's move on to the solution. Let us decompose the force of gravity of the load into components: one component is directed along the inclined plane, and the other is perpendicular to it. The force of pressure of the load on body 2 is equal to the projection of the force of gravity on the axis perpendicular to the direction of movement of body 2.

Thus, the force of pressure of load 1 on body 2 is equal to m1 * g * sin(a), where g is the acceleration of free fall, a is the angle of inclination of the plane. Substituting the numerical values, we get: pressure force = 1 * 9.8 * sin(angle) = 6.76 N.

Thus, the pressure force of load 1 on body 2 is 6.76 N.

Solution to problem 13.7.3 from the collection of Kepe O.?.

We present to your attention the solution to problem 13.7.3 from the collection of problems in physics by Kepe O.?. in electronic format.

In solving this problem, we consider the process of moving a load 1 weighing 1 kg down an inclined plane interacting with a body 2 moving with an acceleration of 2 m/s2 down a vertical guide.

The solution to the problem is based on the application of Newton's second law of motion, and is calculated taking into account all the necessary physical formulas and numerical values.

By purchasing this solution to the problem in electronic format, you get convenient and quick access to a complete and detailed solution to the problem, without having to waste time searching for materials and calculations on your own.

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Product description:

Solution to problem 13.7.3 from the collection of problems in physics by Kepe O.?. is an electronic document containing a complete and detailed solution to this problem. In the problem, two bodies are given: a load weighing 1 kg and body 2 moving with an acceleration of 2 m/s2 down a vertical guide. Load 1 descends down an inclined plane, which makes a certain angle with the horizon.

To solve the problem, Newton's second law of motion is used, according to which the force acting on a body is equal to the product of the body's mass and its acceleration. The force of pressure of the load on body 2 is found by decomposing the force of gravity of the load into its components and finding the projection of the force of gravity on the axis perpendicular to the direction of movement of body 2.

The solution to the problem contains all the formulas and numerical values ​​necessary to calculate the pressure force of load 1 on body 2. By purchasing this solution to the problem, you get convenient and quick access to a complete and detailed solution to the problem, which allows you to save time on independently searching for materials and calculations.

The answer to problem 13.7.3 from the collection of Kepe O.?. equal to 6.76 N.

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Solution to problem 13.7.3 from the collection of Kepe O.?. consists in determining the pressure force of load 1 on body 2 when the load moves down an inclined plane.

From the conditions of the problem it is known that the mass of load 1 is equal to 1 kg, and body 2 moves downward with acceleration a2 = 2 m/s2. It is necessary to determine the pressure force of load 1 on body 2.

To solve the problem, you can use Newton’s law, the second law of dynamics, which states that the force acting on a body is equal to the product of the body’s mass and its acceleration:

F = m * a

where F is the force acting on the body, m is the mass of the body, a is the acceleration of the body.

Applying this law to body 2, we get:

F2 = m2 * a2

where F2 is the force acting on body 2, m2 is the mass of body 2, a2 ​​is the acceleration of body 2.

Since body 2 is moving downward, the direction of force F2 will be directed upward, opposite to the direction of movement of the body.

According to Newton's third law, action and reaction are equal in magnitude and opposite in direction. Thus, the force acting on load 1 from body 2 will be equal to the force acting on body 2 from load 1.

Thus, the pressure force of load 1 on body 2 will be equal to:

F1 = m1 * a2 = 1 kg * 2 m/s2 = 2 N

Answer: the pressure force of load 1 on body 2 is 2 N (newtons).

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