What force is required for fracture during compression of the femoral

what bones?

I will be able to answer your question, but I would like to point out that it is best to ask questions in English, as I am specifically trained in English and can answer your questions more accurately and completely in this language. However, I will answer your question in Russian.

The force required to fracture the femur when compressed depends on many factors, such as its size, shape, structure and health. However, on average, it may take about 4,000 Newtons of force (about 408 kilograms of force) to break a femur bone under compression. This value can vary depending on many factors and is given here only as a general idea of ​​what forces may be required to fracture bone.

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what bones?

I am ready to answer your question in Russian!

In order for the femur to break under compression, a certain amount of force is required, which can vary depending on a number of factors, such as the age and health of the person, and the direction and magnitude of the force applied.

On average, it takes between 4,000 and 7,000 Newtons of force to break a femur under compression. However, it should be remembered that the femur is one of the strongest bones in the human body, so such injuries can only be caused by significant impacts, such as a fall from a height or a car accident.

In any case, a fractured femur is a serious injury that requires immediate medical attention. If you suspect such an injury, consult a doctor immediately.

To solve this problem, it is necessary to use Hooke's law, which describes the dependence of the deformation of a body on the force applied to it. According to this law, the stress σ that occurs when a body is compressed or stretched is proportional to the ratio of the applied force F to the cross-sectional area of ​​the body S:

σ = F / S

Also, to solve the problem, you need to know that the tensile strength of the bone is 1.4 * 10^8 Pa, which means the maximum stress that the bone can withstand without destruction.

To determine the required force F for fracture during compression of the femur, you must first determine the stress σ that occurs when the bone is compressed by a certain force F. To do this, you need to calculate the cross-sectional area of ​​the bone S, which is determined by the formula:

S = π * (d/2)^2

where d is the diameter of the bone.

Thus, for a given bone with a diameter of 30 mm, the cross-sectional area will be equal to:

S = π * (30 mm / 2)^2 = 706.9 mm^2

Now we can calculate the stress σ that occurs when a bone is compressed by a force F:

σ = F / S

Knowing the tensile strength of the bone, we can calculate the maximum permissible force F that the bone can withstand without destruction:

F = σ * S = (1.410^8 Pa) * (706.9 mm^2) = 9.88510^6 N

Thus, a force of approximately 9.9 million Newtons is required to fracture a femur with a diameter of 30 mm and a wall thickness of 3 mm in compression.

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