Two current sources with electromotive forces E1 = 12 V and

There are two current sources with different electromotive forces: E1=12 V and E2=8 V. Each source has an internal resistance: R1=4 Ohms and R2=2 Ohms, respectively. In addition, the circuit contains a rheostat with a resistance of R = 20 Ohms.

It is necessary to determine the current flowing in the rheostat and current sources.

Product description

We present to you a digital product - a calculator for calculating current strength in electrical circuits. This handy tool will help you solve problems in electrical engineering and electronics related to determining the current strength in various devices.

The calculator is based on the specified parameters of an electrical circuit, including two current sources with electromotive forces E1=12 V and E2=8 V, having internal resistances R1=4 Ohms and R2=2 Ohms, respectively, as well as a rheostat with a resistance R=20 Ohms. You can easily determine the current strength in each of the circuit elements using our calculator.

Our calculator has a simple and intuitive interface that allows you to quickly and easily enter circuit parameters and obtain results. It also has a beautiful html design, which makes using the calculator even more enjoyable.

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There is an electrical circuit consisting of two current sources and a rheostat. The first source has an electromotive force E1 = 12 V and internal resistance R1 = 4 Ohms, the second source has an electromotive force E2 = 8 V and internal resistance R2 = 2 Ohms. The rheostat has a resistance of R = 20 Ohms.

We need to determine the current strength in the rheostat and current sources.

To solve this problem, we can use Ohm's law, which states that the current (I) in an electrical circuit is proportional to voltage (V) and inversely proportional to resistance (R): I = V / R.

For a current source with ΔDC E1 and internal resistance R1, the current strength will be I1 = E1 / (R1 + R), where R is the resistance of the rheostat.

For a current source with ?DS E2 and internal resistance R2, the current strength will be I2 = E2 / (R2 + R).

The current strength in the rheostat will be equal to the sum of the currents passing through both sources: I = I1 + I2.

Using the values ​​given in the condition, we can calculate the current in each element of the circuit:

I1 = 12 / (4 + 20) = 0.5 A I2 = 8 / (2 + 20) = 0.4 A I = I1 + I2 = 0.5 + 0.4 = 0.9 A

Thus, the current in the rheostat is 0.9 A, and the current in the current sources is 0.5 A and 0.4 A, respectively.

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This product is task No. 31563, related to the determination of current strength in a circuit consisting of two current sources and a rheostat.

We have two current sources with electromotive forces E1=12 V and E2=8 V and internal resistance R1=4 Ohms and R2=2 Ohms, respectively, as well as a rheostat with resistance R=20 Ohms, which are connected as shown in the figure.

It is necessary to determine the current strength in the rheostat and current sources. To solve the problem, Kirchhoff's and Ohm's laws are used.

According to Kirchhoff's law, the sum of electrical currents going to a node must be equal to the sum of electrical currents coming from the node.

According to Ohm's law, the current in a circuit is proportional to the voltage and inversely proportional to the resistance of the circuit.

To determine the current strength in a circuit, it is necessary to use these laws and apply formulas from which it follows that the current strength in the circuit is equal to the ratio of the voltage to the sum of the circuit resistance.

A detailed solution to the problem with a brief description of the conditions, formulas and laws used in the solution, the derivation of the calculation formula and the answer can be found in the corresponding source, where all the necessary calculations and explanations are given. If you have any questions about the solution, you can contact the author of the problem or another qualified specialist.

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